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Diano4ka-milaya [45]
3 years ago
13

Which of the following are conjugate acid/base pairs? Select all that apply.

Chemistry
1 answer:
Setler79 [48]3 years ago
7 0

Answer: HCOOH and HCOO^-

HNO_3 and NO_3-^-

H_2SO_4 and SO_4^{2-}

H_2CO_3 and CO_3^{2-}

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equations:

1. HCOOH(aq)\rightarrow HCOO^-(aq.)+H^+(aq.)

Here, HCOOH is loosing a proton, thus it is considered as an acid and after losing a proton, it forms HCOO^- which is a conjugate base.

2. HNO_3(aq)\rightarrow NO_3^-(aq.)+H^+(aq.)

Here, HNO_3 is loosing a proton, thus it is considered as an acid and after losing a proton, it forms NO_3^- which is a conjugate base.

3. H_2SO_4(aq)\rightarrow SO_4^{2-}(aq.)+2H^+(aq.)

Here, H_2SO_4 is loosing a proton, thus it is considered as an acid and after losing a proton, it forms SO_4^{2-} which is a conjugate base.

4. NaCl and NaOh are not conjugate acid/ base pairs.

5. H_2CO_3(aq)\rightarrow CO_3^{2-}(aq.)+2H^+(aq.)

Here, H_2CO_3 is loosing a proton, thus it is considered as an acid and after losing a proton, it forms CO_3^{2-} which is a conjugate base.

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5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7
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Answer:

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Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

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Molar mass CO2 = 44.01 g/mol

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Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

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Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 =  0.385 moles

Moles C = 1* 0.385 = 0.385 moles

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Moles H2O = 0.192 moles

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Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

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Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

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We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

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This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

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