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madam [21]
3 years ago
7

What happens to the partial pressure of oxygen in a sample of air if the temperature is increased?

Chemistry
2 answers:
aalyn [17]3 years ago
8 0

it increases.

Hope this helps

:)

ludmilkaskok [199]3 years ago
6 0

Air is mainly composed of N2  (78%), O2 (21%) and other trace gases. Now, the total pressure of air is the sum of the partial pressures of the constituent gases. The partial pressure of each gas, for example say O2, can be expressed as:

p(O2) = mole fraction of O2 * P(total, air)  ----(1)

Thus, the partial pressure is directly proportional to the total pressure. If we consider a sealed container then, as the temperature of air increases so will its pressure. Based on equation (1) an increase in the pressure of air should also increase the partial pressure of oxygen.

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Tap water used for drinking is considered in the DIL calculations.<br> A. True<br> B. False
guajiro [1.7K]

Tap water used for drinking is considered in the DIL calculations; true
7 0
3 years ago
What were the first 5 planets that were observed? Why were those the only ones? Help pls!
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2 years ago
What is the density of ammonia (NH3) at 293 K and 0.913 atm?
Anastaziya [24]

Answer:  The density of  Ammonia is 0.648 g/l

Explanation:

Density = Mass/ Volume

Mass of one mole of  Ammonia (NH3) = 17.031g

Volume =?

Using the ideal gas law we can determine the volume.

PV = nRT

P = 0.913 atm, V= ?, n = 1, R = 0.08206 L.atm/K, and T= 293K

Make V the subject of the formular, we then have;

V= nRT/ P = 1 mol x 0.08206 L.atm/ K.mol x 293 / 0.913 atm

               V = 24.04358/ 0.913 = 26.3L

Having gotten the value of Volume in this question, we then go back to solve for density.

Density = Mass/ Volume

                17.031g/ 26.3L = 0.64756 ≈ 0.648 g/l

7 0
2 years ago
What is the molarity of a nitric acid solution if 43.13 mL 0.1000 M KOH solution is needed to neutralize 30.00 mL of the acid so
Leno4ka [110]

Answer:

0.144M

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

HNO3 + KOH —> KNO3 + H20

From the equation,

nA = 1

nB = 1

From the question given, we obtained the following:

Ma =?

Va = 30.00mL

Mb = 0.1000M

Vb = 43.13 mL

MaVa / MbVb = nA/nB

Ma x 30 / 0.1 x 43.13 = 1

Cross multiply to express in linear form

Ma x 30 = 0.1 x 43.13

Divide both side by 30

Ma = (0.1 x 43.13) /30 = 0.144M

The molarity of the nitric acid is 0.144M

8 0
2 years ago
Can yall plz help me it’s a huge major grade and i don’t know how to do this
fomenos

Answer:

1. 48 mols

2. 0.2 M

5. 1.25 L

Explanation:

Molarity= mols divided by liters

Hope this helps not sure about 3 and 4

3 0
3 years ago
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