the products formed from the reaction
all of the above
solution:
the given compounds are sodium acetate, 1M HCL,NaHCO₃ and Na2CO₃
pH of the buffer solution is 4.7
the value of pKa of sodium bicarbonate is 6.37
the value of pKa of acetic acid is 4.7
calculate concentration of acetic acid by using the following forumula
pH=pKa+lag[salt]/[acid]
substitute the pH and Pka values in the formula.
4.7=4.7+log[salt]/[acid]
log[salt]/[acid]=0
thus, the concentration ratio of the salt and acid should be equal to each other.
Thus, concentration of sodium acetate is 0.05M
Concentration of sodium acetate= concentration of acid
= 0.05M
Volume of the buffer solution is 100mL
The buffer solution can be prepared as 0.05M of 50mL sodium acetate will react with 0.05M of 50mL of 0.05M of HCL.
The chemical equation for neutralization of the weak base with strong can be represented as show as
CH₃COONa+HCL-->CH₃COOH+NaCL
A bicycle rusting after it is left in the rain is an example of a chemical reaction because it involves oxidation (Option d).
<h3>What is a chemical reaction?</h3>
A chemical reaction can be defined as a phenomenon in which one or more substances called reactants react to form one or more different compounds, which are known as products.
A chemical reaction may include an enzyme that works to increase the seed of the reaction in normal conditions by lowering the activation energy of the reaction.
Therefore, we can conclude that a chemical reaction such as oxidation in a bicycle is a process where reactants combine or break down to form the products of such reaction.
Complete question:
Which of the following situations contains an example of a chemical reaction?
a. Ice forming after water is placed in a freezer
b. Watercolor paint drying on paper
c. a sugar cube dissolving in a glass of water
d. a bicycle rusting after it is left in the rain
Learn more about chemical reactions here:
brainly.com/question/11231920
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Answer:
184.62 ml
Explanation:
Let
and
be the initial and
and
be the final pressure, volume, and temperature of the gas respectively.
Given that the pressure remains constant, so
...(i)
= 200 ml
K
K
From the ideal gas equation, pv=mRT
Where p is the pressure, v is the volume, T is the temperature in Kelvin, m is the mass of air in kg, R is the specific gas constant.
For the initial condition,

For the final condition,

Equating equation (i), and (ii)

[from equation (i)]

Putting all the given values, we have

Hence, the volume of the gas at 3 degrees Celsius is 184.62 ml.