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gregori [183]
3 years ago
9

HELP PLEASEEEEEE I BEG U

Chemistry
2 answers:
cupoosta [38]3 years ago
6 0

Answer:

3.) Mercury

5.) Uranium -235

6.) Bromine

9.) Tungsten

10.) Silver

11.) Silicon

vagabundo [1.1K]3 years ago
3 0

Answer:

1.Calcium 2.Hydrogen 3.Mercury 4.Mendelevium 5.Uranium 6.bromine 7.einsteinium 8.palladium 9.Tungsten 10.Silver 11.Sillicon

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Between Lab Period 1 and Lab Period 2, design a separation scheme for all 4 cations. Use the results of your preliminary tests a
fiasKO [112]

Answer:

                    SEPARATION SCHEME FOR  CATIONS

GIVEN  CATIONS : Ag^{+} \ ,  Fe^{3+} , Cu^{2+}, Ni^{2+}

     

    Step 1:   Add 6mol/dm^3 of HCl to the mixture solution

    Result : This would cause a precipitate of AgCl to be formed

    Reaction :  Ag^{+} _{(aq)} + Cl^{-} _{(aq)}  ---------> AgCl(ppt)

    Step 2 : Next is to remove the precipitate and add H_2S to the remaining          

                 solution in the presence of 0.2 \ mol/dm^3 of HCl

     Result : This would cause a precipitate of CuS to be formed

     Reaction :  Cu^{2+}_{(aq)} + S^{2-}_{(aq)} ------> Cu_2S(ppt)

 

     Step 3: Next remove the precipitate then add 6 \ mol/dm^3 of aqueous      

                 NH_3 (NH_3 \cdot H_2 O) , process the solution in a centrifuge,when the  

                 process  is done then sort out the  precipitate from the  solution

                 Now this precipitate is   Fe(OH)_3 and the remaining solution

                contains  (Ni (NH_3)_6)

                 Next take out the precipitate to a different beaker and add HCl

                to it   this will dissolve it, then add a drop of NH_4SCN this will

                form  a precipitate  Fe(SCN)_{6}^{3-} which will have the color of

                 blood  indicating the presence of Fe^{3+}

             

   Reaction :   F^{3+}_{(aq)} + 30H^-_{(aq)} --------->Fe(OH)_3_{(aq)}

                        Fe (OH)_{(s)} _3  + 3H^{+}_{aq} -------> Fe^{3+}_{aq} + 3H_2O_{(l)}

                         Fe^{3+} + 6SCN^{-} -----> Fe(SCN)_6 ^{3-}

                      Now the remaining mixture contains Ni^{2+}

     

       

Explanation:

6 0
3 years ago
What is the volume of an object with a density of 24.5 g/cm³ and a mass of 8.2 g?
vitfil [10]

<u>Answer:</u> The correct answer is option A.

<u>Explanation:</u>

To calculate the volume of an object, we use the formula:

Density=\frac{\text{Mass of an object}}{\text{Volume of an object}}

We are given:

Density of an object = 24.5g/cm^3

Mass of an object = 8.2 grams

Volume of an object = ?

Putting values in above equation, we get:

24.5g/cm^3=\frac{8.2g}{Volume}

Volume=0.33cm^3

Hence, the correct answer is Option A.

6 0
3 years ago
A sample of air is composed of nitrogen, oxygen, and argon gases. if the partial pressure of nitrogen is 587 mm hg, oxygen is 15
oksian1 [2.3K]
The total  pressure  is calculated as below

Total  pressure = partial pressure of (nitrogen +oxygen + argon gas)

= 587 mm hg + 158 mm hg + 7 mm hg = 752  mmhg  is the  total pressure
3 0
3 years ago
Read 2 more answers
In which pair do both atoms have one electron only in an s orbital in their ground states?
lora16 [44]
The answer to this is letter D.

Chromium's electron configuration is <span>1s2 2s2 2p6 3s2 3p6 3d5 4s1, where the last electron is in the s orbital with only 1. As for Li, it is found in the group 1 metals, and it is a fact that all elements under this group has the their last electron to be in the s orbital with only one electron in their outermost shell. 

</span>The electron configuration<span> associated with the lowest energy level of the atom is referred to as </span>ground state and each electron ion is in the lowest energy level possible. When the moment comes that electrons go into a higher level of energy, that is what we call the excited state. 
4 0
3 years ago
Which kind of nuclear decay does not alter the identity of the atom?
PtichkaEL [24]
For alpha and beta decay it does because the proton number changes.
During gamma, there is no change of identity, just energy
5 0
3 years ago
Read 2 more answers
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