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gregori [183]
2 years ago
9

HELP PLEASEEEEEE I BEG U

Chemistry
2 answers:
cupoosta [38]2 years ago
6 0

Answer:

3.) Mercury

5.) Uranium -235

6.) Bromine

9.) Tungsten

10.) Silver

11.) Silicon

vagabundo [1.1K]2 years ago
3 0

Answer:

1.Calcium 2.Hydrogen 3.Mercury 4.Mendelevium 5.Uranium 6.bromine 7.einsteinium 8.palladium 9.Tungsten 10.Silver 11.Sillicon

You might be interested in
Which formula can be used to calculate the theoretical yield?
Bas_tet [7]

Answer:

Option C, (Actual yield ÷ percent yield) × 100

Explanation:

Theoretical yield is defined as the total amount of product formed for given reactants in a chemical reaction.  It is an ideal case which assumes no exceptions or wastage.

The mathematical relation between the actual yield, percent yield and theoretical yield is as follows -

P.Y. = \frac{M_{A.Y.}}{M_{T.Y.}} * 100

Where

P.Y. represents the percent yield a

M A.Y. represents the mass obtained from actual yield

M T.Y. represents the mass obtained from theoretical yield

Hence, if we rearrange the formula, we get -

M_{T.Y.} = \frac{M_{A.Y.}}{P.Y.} * 100

Hence, option C is correct

5 0
2 years ago
Who wants to be mine
andrew11 [14]

hellow! how r you? 。◕‿◕。

Explanation:

nice to know you then:)

8 0
2 years ago
During which phase does earth see more than half of the moons surface?
Amanda [17]

Answer:

waxing crescent phase

8 0
3 years ago
Read 2 more answers
15g of magnesium (II) oxide decomposes, find the number of oxygen particles produced at 100% yield.
erastova [34]

2.258625 *10²³ oxygen atoms will be produced.

<h3><u>Explanation:</u></h3>

Decomposition reaction is defined as the type of reaction where one single reactant breaks to produce more than one product only by means of heat or other external factor.

Formula of magnesium oxide = MgO.

The molecular mass of magnesium oxide = 24 +16= 40.

So in 40 grams of magnesium oxide, number of molecules is 6.023 * 10²³.

So in 15 grams of magnesium oxide,, number of molecules is 6.023 *1023 * 15/40 = 2.258625 *10²³.

From one molecule of magnesium oxide, one oxide atom will be produced.

So number of oxide atoms with 100% yeild = 2.258625 *10²³

6 0
3 years ago
What mass (in grams) of silver contains the same number of atoms as 5.59 grams of sulfur?
Amanda [17]

Answer:

18.84 g of silver.

Explanation:

We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:

From Avogadro's hypothesis,

1 mole of sulphur contains 6.02×10²³ atoms.

1 mole of sulphur = 32 g

Thus,

32 g of sulphur contains 6.02×10²³ atoms.

Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.

From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.

Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.

This is illustrated below:

1 mole of silver = 6.02×10²³ atoms.

1 mole of silver = 108 g

108 g of silver contains 6.02×10²³ atoms.

Therefore, Xg of silver will contain 1.05×10²³ atoms i.e

Xg of silver = (108 × 1.05×10²³)/6.02×10²³

Xg of silver = 18.84 g

Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur

7 0
2 years ago
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