Answer:
V NH3 = 304.334 L
Explanation:
- 1 mol ≡ 6.02 E23 molecules
⇒ moles NH3 = (7.50 E24 molecules)×(mol/6.022 E23 molecules)
⇒ mole NH3 = 12.454 mol
assuming ideal gas:
STP:
∴ T = 25°C ≅ 298 K
∴ P = 1 atm
⇒ V NH3 = RTn/P
⇒ V NH3 = ((0.082 atm.L/K.mol)×(298 K)×(12.454 mol))/(1 atm)
⇒ V NH3 = 304.334 L
Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the change in temperature. It is expressed as:
<span>
Energy = mCΔT
</span><span>Energy = 132 (0.385) (45 - 32.2)
</span><span>Energy = 650.50 J</span>
Answer:
0.1127 grams of Mg is used to produce one gram of silver
Explanation:
Write a balanced equation
Mg(s) +2Ag + (aq) -->
(aq) + 2Ag(s)
The atomic mass of magnesium is 24.31 g/mol and the atomic mass of silver is 107.84g/mol
1 g Ag of silver is produced from [(1 mol Mg)(24.31 g/mol)] /[ (2mol Ag)(107.84g/mol)]
1 g Ag of silver is produced from 0.1127 grams of Mg
0.1127 grams of Mg is used to produce one gram of silver
The molecular geometry is trigonal bipyramidal.