1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irinina [24]
2 years ago
7

(20 Points!!!!!)

Chemistry
2 answers:
Nezavi [6.7K]2 years ago
4 0
A) Chemical Change .........
trasher [3.6K]2 years ago
3 0

i am pretty sure it would be a chemical change so A

You might be interested in
Sugar dissolves readily in water because it is a(n) ____ substance.
Mnenie [13.5K]
The answer to this question would be D. Hydrophilic.

The word hydrophilic mean attracted by water. That means the molecule has a force to attract water molecule, thus be able to dissolve in water.  The polarity of the molecule would determine whether a molecule hydrophilic or not.
Its opposite would be hydrophobic which the molecule can't dissolve in water.  One example of this would be oil or fat. That is why sometimes it is called lipophilic too.
3 0
3 years ago
A Wisconsin farmer taps a maple tree and collects 200 liters of sap. He determines the sucrose (C12H2011) concentration to be 0.
Minchanka [31]

Answer:

6.0 L

Explanation:

Use the dilution equation M1V1 = M2V2

M1 = 0.075 M

V1 = 200 L

M2 = 2.5 M

V2 = ?

Solve for V2 --> V2 = M1V1/M2

V2 = (0.075 M)(200 L) / (2.5 M) = 6.0 L

4 0
2 years ago
If 14c-labeled uracil is added to the growth medium of cells, what macromolecules will be labeled?
ziro4ka [17]
When there are 14c-lable uracil that are added to the growth medium of cells, the macromolecules that will be labled are RNA. Uracil is a nucleobase that make up the DNA or the RNA. In RNA, uracil binds with other nucleobase (adenine) through hydrogen bonds.
6 0
3 years ago
Read 2 more answers
Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
garri49 [273]

Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

                                = \frac{5.25}{9.85}

                                = 0.527  

Calculate the dew point as follows.

                     y_{1} = 0.5,      y_{2} = 0.5  

          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

           \frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}

             \frac{1}{P} = 0.101966 bar^{-1}              

                             P = 9.807

Composition of the liquid phase is x_{i} and its formula is as follows.

                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{9.2}

                               = 0.5329

                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
3 years ago
C12H22011+1202-->12CO2+11H20
kogti [31]

Answer:

0.185moles

Explanation:

Given parameters:

Volume of O₂  = 49.8L

Unknown:

Number of moles of sucrose required  = ?

Solution:

We can assume that the reaction takes place at standard temperature and pressure.

From this, we can find the number of moles of oxygen that reacted and extrapolate to that of sucrose.

Chemical equation;

           C₁₂H₂₂0₁₁  +  120₂   →   12CO₂   +   11H₂0

Number moles  = \frac{volume of gas}{22.4}   at STP

Number of moles of oxygen gas = \frac{49.8}{22.4}   = 2.22moles

           12 moles of oxygen gas combines with  1 mole of sucrose

       2.22 moles of oxygen gas will combine with \frac{2.22}{12}   = 0.185moles

4 0
3 years ago
Other questions:
  • Which statements are true of geothermal energy? Check all that apply.
    12·2 answers
  • It’s cold outside and you decide to cook some pasta. As you boil the noodles, the kitchen window begins to fog up. Which process
    7·2 answers
  • Which is a correct set of values of m for one of the subshells of n = 2? –1, 0, 1 –1, –2, 0, 1, 2 –1, –2, –3, 0, 1, 2, 3 –1, –2,
    14·1 answer
  • A solution has a pH of 2.5. What is its [OH-] ?
    15·1 answer
  • What is the role of nitric acid during silver nitrate test for halide?​
    10·1 answer
  • 99<br> 96<br> 040Zr<br> +<br> 42He<br> ----&gt;<br> + "42Mo
    5·1 answer
  • How many moles are in 25.0 grams of HF?
    6·2 answers
  • Which of the following involves a chemical change?
    11·2 answers
  • Hi! I produce proteins inside the cell. What am I?​
    13·2 answers
  • How many atoms can be found in a sample of 75g of silicon
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!