MNaHCO₃: 23+1+12+(48×3) = 84g
mCH₃COOH: 12+(1×3)+12+(16×2)+1 = 60g
.................
84g NaHCO₃ react with 60g CH₃COOH
83g NaHCO₃ react with...........
84g ----- 60g
83g ----- X
X = 59,29g CH₃COOH
We used 70g CH₃COOH, it' too much.
So, acetic acid is excess reagent, and sodium bicarbonate is limiting reagent.
_______________________________
B) Amount of CH3COOH is in excess.
:•)
The average speed of the horse for the entire motion is 66.67 m/s.
The given parameters;
- <em>distance traveled by the horse, d = 1 km = 1,000 m</em>
- <em>time of motion of the horse, t = 15 s</em>
The average speed of the horse is calculated by dividing the total distance traveled by the horse by the time of motion.
The average speed of the horse is calculated as follows;

Thus, the average speed of the horse for the entire motion is 66.67 m/s.
Learn more here: brainly.com/question/17289046
The answer is 'equal'. Hydroxide ions are OH- and Hydrogen ions are H+. Have you noticed they're opposite charges? Positive + negative = neutral. That's all there is to it :)
Answer: 
Explanation: The given chemical reaction is:

Equilibrium constant (Kc) in general is written as:
![K_c=\frac{[products]}{[reactants]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5Bproducts%5D%7D%7B%5Breactants%5D%7D)
Note:- Coefficients are written as their powers
So, the Kc expression for the above reaction will be:
![K_c=\frac{[NO]^2[Br_2]}{[NOBr]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO%5D%5E2%5BBr_2%5D%7D%7B%5BNOBr%5D%5E2%7D)
Equilibrium moles are given for all of them. Let's divide the moles by given liters to get the concentrations.
= 0.040 M
= 0.0658 M
= 0.0217 M
Plug in the values in the equilibrium expression to calculate Kc.

