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luda_lava [24]
3 years ago
13

How many solutions does the system have?

Mathematics
2 answers:
klasskru [66]3 years ago
8 0

Answer:

wait ok

Step-by-step explanation:

jolli1 [7]3 years ago
4 0

Answer:

C. Infinitely Many Solutions.

Step-by-step explanation:

Look at attachment:

Hope this helps! :)

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The absolute value of opposite numbers is the same? <br><br> True or False?<br><br> Why or Why not
NeTakaya

Answer:

false, it's the opposite so its doesn't have the same amount, negative or positive.

8 0
3 years ago
a washer and a dryer cost 659$ combined. The washer costs 91$ less than the dryer, how much was the dryer?  
Darina [25.2K]
W+D=659

W=D-91

---------------------------

(D-91)+D=659

D-91+D=659

2D=750

D=750/2=375

------------------------------

W+375=659

W=284

------------------------------

So the dryer had cost $375 and the washer had cost $284.
7 0
3 years ago
Read 2 more answers
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
I need help please! I need to know what is/how to get a,b, and c for factoring trinomials of the problem (x-3)(x+4)=0.
Readme [11.4K]

Answer: Trinomials often (but not always!) have the form x2 + bx + c. ... So, how do you get from 6x2 + 2x – 20 to (2x + 4)(3x −5)? Let's take a look. Factoring Trinomials

Step-by-step explanation:

6 0
3 years ago
Show that 2x +1 is a factor of 2x3 +5x2+4x+1 and factories completely
larisa [96]

\text{According to the factor theorem, if f(b) = 0, then x-b is a factor of f(x).}\\\\\text{Given that,}\\\\f(x) = 2x^3 +5x^2 +4x +1 \\\\f\left(-\dfrac 12 \right) = 2\left( - \dfrac 12 \right)^3 +5 \left( - \dfrac 12 \right)^2 +4 \left( - \dfrac 12 \right) +1 \\\\\\~~~~~~~~~~~~=-2 \cdot \dfrac 18 + 5 \cdot \dfrac 14 -2 +1 \\\\\\~~~~~~~~~~~=\dfrac 54 -\dfrac14 -1\\\\\\~~~~~~~~~~~=\dfrac 44 -1 \\\\\\~~~~~~~~~~~=1-1\\\\\\~~~~~~~~~~~=0\\\\\text{So,}~ 2x +1 ~ \text{is a factor of f(x).}

\text{Now,}\\\\f(x) = 2x^3 +5x^2 +4x +1 \\\\~~~~~~=2x^3+x^2 +2x^2 +2x +2x+1\\\\~~~~~~=x^2(2x+1)  +2x(2x+1) +  (2x+1)\\\\~~~~~~=(2x+1)(x^2 +2x +1)\\\\~~~~~~=(2x+1)(x+1)^2

3 0
2 years ago
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