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3 years ago

5

Prehistoric cave paintings were discovered in a cave in france. the paint contained 24 %24% of the original carbon-14. use the

exponential decay model for carbon-14, upper a equals upper a 0 e superscript negative 0.000121 ta=a0e−0.000121t, to estimate the age of the paintings. the paintings are approximately 1179411794 years old. (round to the nearest integer.) question is complete.

1 answer:

serious [3.7K]3 years ago

5 0

Answer:

t = 11,794 years

Step-by-step explanation:

If you are looking for a confirmation that your answer is correct, it is.

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I need help with this problem ASAP

omeli [17]

Answers: 7x^2y^2 -3x+6y

I am not sure how to explain it but here you go

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2 years ago

Evaluate the following f(-2)+f(-3)=

8090 [49]

It would be =-5f
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3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

Find the number that makes the ratio equivalent to 1:4.

amid [387]

8:2 hope this helps

7 0

3 years ago

Read 2 more answers

6 - 2x = 6x - 10x + 4

yarga [219]

$6 - 2x = 6x - 10x + 4$

$6 - 2x = - 4x + 4$

$6 = - 4x + 4 + 2x$

$6 = - 2x + 4$

$- 2x + 4 = 6$

$- 2x = 6 - 4$

$- 2x = 2$

$x = \frac{ \: \: \: 2}{ - 2}$

$x = - 1$

Therefore , the value of x = -1

6 0

3 years ago