Answer:
The probability that none of the meals will exceed the cost covered by your company is 0.2637.
Step-by-step explanation:
A hyper-geometric distribution is used to define the probability distribution of <em>k</em> success in <em>n</em> samples drawn from a population of size <em>N</em> which include <em>K</em> success. Every draw is either a success of failure.
The random variable <em>X</em> = number of meals that will exceed the cost covered by the company.
The random variable <em>X</em> follows a hyper-geometric distribution.
The information provided is:
N = 15
K = 3
n = 5
k = 0
The probability mass function of a hyper-geometric distribution is:
Compute the probability that none of the meals will exceed the cost covered by your company as follows:
Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.
Answer:
y = x - 13
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = x - 9 ← is in slope- intercept form
with slope m = 1
Parallel lines have equal slopes, thus
y = x + c ← is the partial equation of the parallel line
To find c substitute (6, - 7) into the partial equation
- 7 = 6 + c ⇒ c = - 7 - 6 = - 13
y = x - 13 ← equation of parallel line
Answer:
a: the second choice, and pounds=10
b. the second choice, and points=90.
Step-by-step explanation:
for a , you just divide the pounds by the price and you get 5 for each.
for b, you just divide the points by the tickets and you get 9 each.
Answer: P(odd) = 0.499
Step-by-step explanation:
Given:
Total number of people = 20
Number of men = 12
Number of women = 8
Number of jury to be selected = 6
For the jury to have an odd number of women. it must have either of the three.
1. 1 woman , 5 men
2. 3 women, 3 men
3. 5 women, 1 man
The total possible ways of selecting the 6 people jury is;
N = 20C6 = 20!/6!(20-6)!
N = 38760
The possible ways of selecting;
Case 1 : 1 woman, 5 men
N1 = 8C1 × 12C5
N1 = 8 × 792 = 6336
Case 2 : 3 women , 3 men
N2 = 8C3 × 12C3
N2 = 12320
Case 3 : 5 women, 1 man
N3 = 8C5 × 12C1
N3 = 672
P(Odd) = (N1+N2+N3)/N
P(odd) = (6336+12320+672)/38760
P(odd) = 19328/38760
P(odd) = 0.499
Answer:
x = 4
y = 1
Step-by-step explanation:
x = 3y + 1 (Multiply everything by -2)
2x + 4y = 12 (Transfer 4y to the right of the = sign)
2x = -4y + 12
-2x = -6y - 2
0 = -10y + 10
-10 = -10y
y = 1
x = 3y + 1
x = 3(1) + 1
x = 3 + 1
x = 4