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Elena-2011 [213]
3 years ago
8

Consider the problem of finding the line of symmetry and vertex of the quadratic equation f(x) =x^2-8x+15 What is the error in t

he solution below?
  x^2-8x+15=0
x=-8/2 =-8/2=-4 line of symmetry
8^2-8x+15=0
 (-4)^2-8(-4)+15=0
16+32+15=0
y=63
(-4,63) vertex 

A.
The solution is correct.
B.
The line of symmetry should have been 4 instead of –4.
C.
The vertex is incorrect; it should have been {–4, 53}.
D.
-4^2 should have been squared as –16 instead of 16.
Mathematics
2 answers:
Nostrana [21]3 years ago
4 0
The answer is A, dont listen to these people


Elenna [48]3 years ago
3 0
\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{llccll} f(x) = &{{ 1}}x^2&{{ -8}}x&{{ +15}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\textit{so the line of symmetry will be at }x=-\cfrac{{{ b}}}{2{{ a}}}
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