Answer: The energy of activation for the chirping process is 283.911 kJ/mol
Explanation:
According to the Arrhenius equation,

The expression used with catalyst and without catalyst is,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate of reaction at
= 194/min
= rate of reaction at
= 47.6 /min
= activation energy
R = gas constant = 8.314 J/Kmol
tex]T_1[/tex] = initial temperature = 
tex]T_1[/tex] = final temperature = 
Now put all the given values in this formula, we get
![\frac{194}{47.6}=\frac{E_a}{2.303\times 8.314}[\frac{1}{278}-\frac{1}{301}]](https://tex.z-dn.net/?f=%5Cfrac%7B194%7D%7B47.6%7D%3D%5Cfrac%7BE_a%7D%7B2.303%5Ctimes%208.314%7D%5B%5Cfrac%7B1%7D%7B278%7D-%5Cfrac%7B1%7D%7B301%7D%5D)

Thus the energy of activation for the chirping process is 283.911 kJ/mol
Volume can be measured in cubic centimetres (which is the small 3 next to the unit and is higher)
Answer:
The criteria listed in order of importance are;
1) To be inflated in the event of a collision in order to protect the occupants of the front of the vehicle
2) To be able to withstand the load of the breaking force of the occupants in the front seat of the vehicle during a collision
3) To be relatively tough so as to resist being torn on impact with a sharp object
The constraints listed in order of importance are;
1) How is the model design able to sense a collision that requires the airbag to be inflated
2) The uncertainty of the load the airbag will withstand upon collision
3) The possible hazard that could be caused by the gas used to inflate the airbag
4) The usage/interaction tendency between the vehicle occupant and the airbag system
Explanation:
In order to produce an effective design, it is important to be able to foresee the possible deficiencies of an idea so as to be able to mitigate the problems before an actual incident happens.
The molar solubility is 7.4×
M and the solubility is 7.4×
g/L .
Calculation ,
The dissociation of silver bromide is given as ,
→
+ 
S
- S S
Ksp = [
] [
] = [S] [ S ] = 
S = √ Ksp = √ 5. 5×
= 7.4×
The solubility =7.4×
g/L
The molar solubility is the solubility of one mole of the substance.
Since , one mole of
is dissociates and form one mole of each
and
ion . So, solubility is equal to molar solubility but unit is different.
Molar solubility = 7.4×
mol/L = 7.4×
M
To learn more about molar solubility ,
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