Question

If 0.00872 mol neon gas at a particular temperature and pressure occupies a volume of 211 mL, what volume would 0.00701 mol neon gas occupy under the same conditions?

Answer 1

Answer:

0.00701 moles of neon gas will occupy 170 ml of volume under the same conditions.

Explanation:

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

$\frac{V_1}{n_1}=\frac{V_2}{n_2}$

where,

$V_1\text{ and }n_1$ are the initial volume and number of moles

$V_2\text{ and }n_2$ are the final volume and number of moles

We are given:

$V_1=211 mL\\n_1=0.00872 mol\\V_2=?\\n_2=0.00701 mol$

Putting values in above equation, we get:

$\frac{211 mL}{0.00872 mol}=\frac{V_2}{0.00701}$

$V_2=\frac{211 mL\tomes 0.00701 mol}{0.00872 mol}=169.62 mL\approx 170 mL$

0.00701 moles of neon gas will occupy 170 ml of volume under the same conditions.