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sasho [114]
3 years ago
11

Assume a population of weights is normally distributed.

Mathematics
1 answer:
borishaifa [10]3 years ago
8 0
The answer is 0.9599
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If you can answer 10, 11, and 12 for me that would be awesome. (12 multiply choice would be in the comments)
fenix001 [56]
10: 3
11: 2
and can’t see 12
5 0
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How old am i if 400 reduced by 4 times my age is 144
Airida [17]

Answer:

400 divied by 4 is 144

so ur 14?

Step-by-step explanation:

5 0
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The line contains the point (-2,-5) and is parallel to 2x-3y = 9.<br> What’s the equation
Karolina [17]

Answer:

y=(2x/3)-(11/3)

Step-by-step explanation:

https://www.emathhelp.net/calculators/algebra-1/parallel-and-perpendicular-line-calculator/

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A bag of candy has a mass of 80 g. A chocolate bar has a mass of 110 g. What is the total mass of the bag of candy and the choco
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3 0
2 years ago
Solve the linear programming problem.
larisa [96]

Answer:

1. Objective function is a maximum at (16,0), Z = 4x+4y = 4(16) + 4(0) = 64

2. Objective function is at a maximum at (5,3), Z=3x+2y=3(5)+2(3)=21

Step-by-step explanation:

1. Maximize: P = 4x +4y

Subject to: 2x + y ≤ 20

x + 2y ≤ 16

x, y ≥ 0

Plot the constraints and the objective function Z, or P=4x+4y)

Push the objective function to the limit permitted by the feasible region to find the maximum.

Answer: Objective function is a maximum at (16,0),

              Z = 4x+4y = 4(16) + 4(0) = 64

2. Maximize P = 3x + 2y

Subject to x + y ≤ 8

2x + y ≤ 13

x ≥ 0, y ≥ 0

Plot the constraints and the objective function Z, or P=3x+2y.

Push the objective function to the limit in the increase + direction permitted by the feasible region to find the maximum intersection.

Answer: Objective function is at a maximum at (5,3),

              Z = 3x+2y = 3(5)+2(3) = 21

7 0
3 years ago
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