Solving Exponential Equations (lacking a common base)(0.52)^q=4
2 answers:
Answer:
q = log4 / log0.53
q = -2.189
Step-by-step explanation:
(0.53)^q = 4
Taking log of both sides!
q log 0.53 = log 4
q = log 4 / log 0.53
q = 0.602 / -0.275
q = - 2.189
This can be checked to confirm correctness.
Substituting q = -2.189
(0.53)^ -2.189 = 1/ 0.249
= 4.01 Proved!
(Note that the "1" is because of the negative sign)
Answer:
q = -2.12
Step-by-step explanation:
lg both sides
lg(0.52^q) = lg4
qlg0.52 = lg4
q = lg4/lg0.52
q = -2.12
You might be interested in
Answer:
A)-1
Step-by-step explanation:
3x-5≥4x-3
3x-4x≥-3+5
-x≥2
x≤-2
(-infinity,-2]
-1 x
-2,-3,-5 ✓
20 days until they work together again
Answer:
so basically first add 700+300 which would come up to 1000. 300+100 is 400 so add 100 to the 1000 and you have 1100
I do not understand your question could you please be more descriptive
Answer:
try 5
Step-by-step explanation:
21+4*5=25
