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bagirrra123 [75]
3 years ago
15

Module 1 Exam

Mathematics
1 answer:
balu736 [363]3 years ago
6 0

Answer:

s[fue =f8erf9re8hf

Step-by-step explanation:

caiee er-gi hre-9ir-8fr- u-9r f09reuhhw-9ofdfokvhwe09uvr9gg

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△ABC is reflected over the x−axis and then reflected over the y−axis to form ΔA''B''C'' as shown below.
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c

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Step-by-step explanation:

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Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

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3 years ago
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olga_2 [115]
“Above the door” is the prepositional phrase but I can’t help you you it’s the second part, sorry.
3 0
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) A store is having a 30% off sale. Michelle uses the expression 0.7p and Stuart uses the expression p-0.3p. Who is using the co
Aleonysh [2.5K]

Answer:michelle

Step-by-step explanation: it is 70% of the cost since it’s 30% of the original

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