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2 years ago

X^2 =1 how many solutions are there

Mathematics

2 answers:

vlada-n [284]2 years ago

7 0

Answer:

x=1, x=-1

Step-by-step explanation:

x^2=1

x=sqrt(1)=+-1

Thus, there are 2 solutions: 1 and -1

HACTEHA [7]2 years ago

5 0

Answer:

Answer:

x=1 or x=−1

Step-by-step explanation:

I think just 2

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vazorg [7]

Answer:

subject?

Step-by-step explanation:

6 0

2 years ago

Using the formula in model 1, choose the correct answers for the total amount and amount of interest earned in the following com

DIA [1.3K]

The total amount is $ 1015.82 and interest amount is $ 165.82

Solution:

The formula for amount when interest is compounded annually is:

$\mathrm{A}=P\left(1+r}\right)^{n}$

Where,

"A" is the total amount

"P" is the principal

"r" is the rate of interest in decimal form

"n" is the number of years

From given, $850 at 2% for 9 years, compounded annually

P = 850

t = 9 years

$r = 2 \% = \frac{2}{100} = 0.02$

Substituting the given values we get,

$A = 850(1+0.02)^9\\\\A = 850 \times 1.02^9\\\\A = 850 \times 1.1950\\\\A = 1015.82$

Thus total amount is $ 1015.82

Interest amount = Total amount - principal

Interest amount = 1015.82 - 850

Interest amount = 165.82

Thus total amount earned is $ 1015.82 and interest amount is $ 165.82

7 0

2 years ago

How is a tangent different from a chord

Akimi4 [234]

In a tangent segment, no part of it is in the interior of the circle. with a secant, there is a part in the interior called the chord. hope it helps
if you need help with anything else just ask me

5 0

2 years ago

Read 2 more answers

Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval [0,π].

Troyanec [42]

Answer:

Arc length $=\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

Arc length $=9.75053$

Step-by-step explanation:

The arc length of the curve is given by $\int_a^b \sqrt{1+[f'(x)]^2}\ dx$

Here, $f(x)=\int_0^{4.5x}sin(t) \ dt$ interval $[0, \pi]$

Now, $f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )$

$f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( -cos(4.5x)+1 \right )$

$f'(x)=4.5sin(4.5x)$

Now, the arc length is $\int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx$

$\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx$

After solving, Arc length $=9.75053$

5 0

3 years ago

16×10=(10+?)×10 =(?×10)+(?×10 =?+? =?

ZanzabumX [31]

16•10=(10+6)•10
=(160•10)+(160•10)
=1600+1600
=320000

4 0

3 years ago

Read 2 more answers