9514 1404 393
Answer:
(a) {(5, 2), (-4, 2), (3, 6), (0, 4), (-1, 2)}
Step-by-step explanation:
The only relation with no repeated x-values is the first one. The first relation is a function.
Answer:
2-sqrt14/2, 2+sqrt13/2.
Step-by-step explanation:
What you do is you have to do the quadratic equation like it says in the problem.
x= −b± sqrtb^2 −4ac
/2a
.
a=-2, b=4, c=5.
x=-4±sqrt(4)^2-4(-2)(5)/2(-2).
x=-4±sqrt16+40/-4.
x=-4±2sqrt14/-2.
2-sqrt14/2, 2+sqrt13/2. is your answer once you have done everything.
you first plug (substitute) in y
-3x - 3(-5x-17)=3
then distribute
-3x+15x+51=3
now combine like terms
12x+51=3
subtract to get 12x by itself
12x=3-51 or 12x=-48
lastly divide by 12 to find x
12x/12=-48/12
x=-4
now find y by plugging x into the other equation
y=-5(-4)-17
y=3
(-4,3)
Hmm yes but yes than yes but yea but then the but yk the but like the and the the
Answer: a) 1 / ⁴⁰C₅ b) 0.33
Step-by-step explanation:
a) The sample space consists of all numbers 1-40.
Since any of the number can be taken from the sample space so each of five 5 distinct numbers we take has equal probability of occurring. So probability of each 5 numbers set we take will be equal to 1 / ⁴⁰C₅
b)
If we pick exactly 3 even number then that means other 2 will be odd.
So, we have sample space of 40 numbers out of which 20 are even and 20 are odd.
Now we have to pick 3 even out of 20 and 2 odd out of 20.
Probability = ²⁰C₃ * ²⁰C₂ / ⁴⁰C₅
Probability= 0.33
