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Afina-wow [57]
3 years ago
15

I need help please!!!

Mathematics
1 answer:
blondinia [14]3 years ago
6 0

Answer:

the correct answerr is b i can see it clearly but from what i see it s b

Step-by-step explanation:

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Triangle L J K is shown. Angle J L K is a right angle. The length of the hypotenuse is 15 inches and the length of the side adja
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The answer is C: cos(x)= 10/15.

Step-by-step explanation:

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<span>A 90 degrees counterclockwise rotation about the origin followed by a translation 1 unit to the left</span>
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What will be the value of the constant term when the function f(x) = 2x^2 -16x +10 is in vertex form?
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(4,-22)

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Write the word sentence as an inequality. Then solve the inequality.
vladimir2022 [97]

Answer:

The inequality is 6x ≥ -24

The solution of this inequality is {x : x ∈ R, x ≥ -4} ⇒ [-4, ∞)

Step-by-step explanation:

  • In the inequality not more than means ≤
  • In the inequality at least means ≥

Let us solve the question

∵ Six times a number x means 6 × x = 6x

∵ At least means ≥

∴ Six times a number x is at least -24 is 6x ≥ -24

∴ The inequality is 6x ≥ -24

Now we will find the solution of the inequality

∵ 6x ≥ -24

→ Divide both sides by 6

∵ \frac{6x}{6} ≥ \frac{-24}{6}

∴ x ≥ -4

∴ The solution of this inequality is {x : x ∈ R, x ≥ -4} ⇒ [-4, ∞)

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The height, h, in feet of a piece of cloth tied to a waterwheel in relation to sea level as a function of time, t, in seconds ca
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Considering the period of the cosine function, it is found that it takes 40 seconds for the wheel to complete one turn.

<h3>What is the period of the cosine function?</h3>

The cosine function is defined by:

f(x) = acos(bx + c) + d.

For the period, we have to look at coefficient b, and the period is:

P = 2π/|B|

For this problem, the function is given by:

h(x) = 15 cos(π/20)

Hence B = π/20, and the period is:

P = 2π/|B| = 2π/(π/20) = 2 x 20 = 40 seconds.

Hence it takes 40 seconds for the wheel to complete one turn.

More can be learned about the period of trigonometric functions at brainly.com/question/12502943

#SPJ1

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2 years ago
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