Find the area of the figure. Use 3.13 for
1 answer:
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Answer:
1) Total outcomes of 1 time = 16
2) 36 times
3) 24 times
Step-by-step explanation:
<h3>1) Total outcomes</h3>If both spinners are spinning together, and are labelled from 1 to 4, the the outcome are:
{(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (2, 4), (3, 1), (3, 2), (3, 3), (3, 4), (4, 1), (4, 2), (4, 3), (4, 4)}
We can count them to find total no. of outcomes
Total outcomes = 16
<h3>2) When Difference = 1</h3>Following combinations have a difference of 1
{(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}
n = 6
Probability of getting such combination is: 6/16
How many times Harvey would get such a combination out of 96 times?
Following combinations have a difference of 0
{(1, 1), (2, 2), (3, 3), (4, 4)}
n=4
Probability of getting such combination is: 4/16
How many times Harvey would get such a combination out of 96 times?
Answer:
126 different symbols can be represented in Morse code
Step-by-step explanation:
We need to sum up the number of sequences using one single place, two places, three places, four places and so on until sequences of six places (dots and dashes).
For each case we use the fundamental counting principle.
For one single place we may have 2 possible sequences (a dash or a dot)
For two places (example: .. or ._) we may have 2*2 sequences, since each place may be filled with either dash or dot (2 possible ways) and then we multiply the ways each place can be filled, thus
Similarly, for three places we may have 2*2*2 sequences, thus
For four places we may have 2*2*2*2 sequences, thus
And so on.
So, notice the total up to arrangements of six symbols, is: