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nordsb [41]
3 years ago
9

What type of system would allow light to enter and exit, but would keep any

Physics
2 answers:
andrew11 [14]3 years ago
4 0
An isolated system , it does not allow any matter or energy to be exchanged
zavuch27 [327]3 years ago
4 0

Answer: it’s closed

Explanation: a pex

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If temperature increases, then pressure _____
miss Akunina [59]

Answer:

it should be increase..

Explanation:

If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.

looked online lol

8 0
3 years ago
Read 2 more answers
A red laser from the physics lab is marked as producing 632.8-nm light. When light from this laser falls on two closely spaced s
BARSIC [14]

Answer:

The wavelength is  \lambda_R  =  649 *10^{-9}\ m

Explanation:

From the question we are told that

   The wavelength of the red laser is  \lambda_r  =  632.8 \ nm =  632.8 *10^{-9}\ m

    The spacing between  the fringe is  y_r  =  6.00\ mm =  6.00*10^{-3}  \  m

   The spacing between  the fringe for smaller laser point  is  y_R   = 6.19 \ mm =  6.19 *10^{-3} \  m

      Generally the spacing between  the fringe is mathematically represented as

       y  =  \frac{D *  \lambda  }{d}

Here  D is the distance to the screen

    and  d is the distance of the slit separation

Now for both laser red light light and  small laser  point  D and  d are same for this experiment

So

         \frac{y_r}{\lambda_r}  =  \frac{D}{d}

=>      \frac{y_r}{\lambda_r}  = \frac{y_R}{\lambda_R}

Where \lambda_R  is the wavelength produced by the small laser pointer

  So

           \frac{6.0 *10^{-3}}{ 632.8*10^{-9}}  = \frac{ 6.15 *10^{-9}}{\lambda_R}

=>       \lambda_R  =  649 *10^{-9}\ m

7 0
3 years ago
Help! Will Mark Brainliest!
boyakko [2]

Answer:

D 5m/s

Explanation:

6 0
3 years ago
Numerical problems:
Sav [38]

Answer:

340 \div 100 \\ 3.4

340cm = 3.4m

Explanation:

When converting units: cm to m, then you need to divide the cm by 100 to get its unit in m.

6 0
4 years ago
Please please help. I don’t understand this.
Kazeer [188]
Which questions do you need help? I could help you
5 0
4 years ago
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