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ohaa [14]
3 years ago
10

A mustang, has an average velocity of 33 m/s while covering a course that is 21 miles long. (1 mile = 1609 m). How long did it t

ake the driver to complete the course?
Physics
1 answer:
saw5 [17]3 years ago
3 0

Answer:

t = 1023.9 seconds

Explanation:

Given that,

The average velocity of a Mustang, v = 33m/s

Distance, d = 21 miles = 33789 m

Let the driver takes t seconds. So,

Speed = distance/time

t=\dfrac{d}{v}\\\\t=\dfrac{33789}{33}\\\\t=1023.9\ s

So, it will take 1023.9 seconds to complete the course.

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Answer:

y = 104.4 ft

Explanation:

As we know that we board in the car of ferris wheel at the bottom position

So we will have

final height of the car at angular displacement given as

y = y_o + R + R sin(270 - 255)

y = y_o + R + R sin 15

here we know that

y_o = 10 ft

R = 75 ft

so we have

y = 10 + 75 + 75 sin15

y = 104.4 ft

4 0
3 years ago
An ideal spring hangs from the ceiling. A 2.15 kg mass is hung from the spring, stretching the spring a distance d = 0.0895 m fr
Igoryamba

Answer:

The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

Explanation:

Given that,

Mass = 2.15 kg

Distance = 0.0895 m

Amplitude = 0.0235 m

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Using newton's second law

F= mg

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kx=mg

k=\dfrac{mg}{x}

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k=\dfrac{2.15\times9.8}{0.0895}

k=235.41\ N/m

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Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

Here, v = A\omega

K.E=\dfrac{1}{2}m\times(A\omega)^2

Here, \omega=\sqrt{\dfrac{k}{m}}^2

K.E=\dfrac{1}{2}m\times A^2\sqrt{\dfrac{k}{m}}^2

K.E=\dfrac{1}{2}kA^2

Put the value into the formula

K.E=\dfrac{1}{2}\times235.41\times(0.0235)^2

K.E=0.06500\ J

Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

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3 years ago
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bagirrra123 [75]
By the law of momentum conservation:-
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=>u¹ + u² = v¹ + v² {as m1=m2}
=>3.5 - 2.75 = v1-1.5
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3 years ago
What do you think will happen to Charlie now that he is smart? Explain.
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