Answer:
x = 0.12 m
Explanation:
Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.
when the box encounters the spring, all the energy of the box is kinetic energy:
the energy relationship between the box and the spring is given by:
1/2(m)×(v^2) = 1/2(k)×(x^2)
(m)×(v^2) = (k)×(x^2)
x^2 = [(m)(v^2)]/k
x = \sqrt{ [(m)(v^2)]/k}
x = \sqrt{ [(0.299)((1.44)^2)]/(44.9)}
x = 0.12 m
Therefore, the mass will travel 0.12 m and come to rest.
= 0.491 m/s
<span>Unless the pig moves static friction acts on it once the pig starts moving kinetic friction comes in to play so when the pig is not moving=frictional force acting on it =normal force*co-efficient of static friction.</span>
No, it's mass remains the same. It's attraction to the planets center AKA gravity changes.
