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Keith_Richards [23]
1 year ago
12

It shows gas particles leaving the car exhaust what procees

Physics
1 answer:
Lubov Fominskaja [6]1 year ago
4 0

The gas particles leaving the car exhaust show the process of combustion.

<h3>What is the process of combustion?</h3>

Combustion refers to a chemical process in which a substance reacts with oxygen to give off heat. The original substance is known as the fuel, whereas the source of oxygen is known as the oxidizer. The fuel can be present in solid, liquid, or gas, but for an airplane, the fuel is usually a liquid form. Combustion also called burning that is the basic chemical process of releasing energy from a fuel and air mixture. In an internal combustion engine, the ignition and combustion of the fuel occurs within the engine. The engine converts the energy from the combustion process to work.

So we can conclude that the car releases gases due to the process of combustion.

Learn more about exhaust here: brainly.com/question/17325487

#SPJ1

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3 years ago
Three equal point charges, each with charge 1.05 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
kirza4 [7]

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The value is U  = 0.06 \  J

Explanation:

From the question we are told that

The value of charge on each three point charge is

q_1 = q_2 = q_3 =q=  1.05 \mu C  =  1.05 *10^{-6} \  C

The length of the sides of the equilateral triangle is r  =  0.500 \

Generally the total potential energy is mathematically represented as

U  = k *  [ \frac{q_1 *  q_2}{r}  +  \frac{q_2 *  q_3}{r}   + \frac{q_3 *  q_1}{r} ]

=> U  = k * 3 * \frac{q^2}{r}

Here k is coulomb constant with value k = 9*10^{9}\  kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

=>    U  = 9*10^9 * 3 * \frac{(1.05 *10^{-6})^2}{0.5 }

U  = 0.06 \  J

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Compute the velocity of light in calcium fluoride which has dielectric constant of 2.056 .​
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