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Degger [83]
2 years ago
12

Use the Phythagorean theorem to find the length of the third side

Mathematics
1 answer:
Doss [256]2 years ago
7 0

x =  \sqrt{69}

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a teacher has three packages of crayons. one package contains 52 crayons, another contains 12 crayons, and the third package con
kotegsom [21]

Answer: 7 crayons

Step-by-step explanation:

To solve we first must find the total number of crayons available by adding up how many crayons are in each container.

         56+12+96 = 160 crayons total

Next we take this number and divide it by 22 (the number of students in the class) to determine how many crayon each student gets

         160 crayons/22 students = 7.272727 crayons per student

However, it's important to note that this number is not a whole number. We must then round down to the nearest whole number because students aren't given fractions of crayons.

         7.272727 ==> 7 crayons per student

5 0
1 year ago
Two squares are similar. The
Pepsi [2]

Answer:

The perimeter of the second square is 36 inches

Step-by-step explanation:

Given

Represent the sides of the squares with S1 and S2.

So:

S_1:S_2 = 1 : 3 --- Scale factor

P_1 =12 --- perimeter of the first

Required

Calculate P2, the perimeter of the second

Represent the ratios of the perimeter:

Scale = P_1 : P_2

Substitute 12 for P1

Scale = 12 : P_2

Equate both scale factors

12 : P_2 = 1:3

Convert to fraction

\frac{12}{P_2} = \frac{1}{3}

Cross multiply

P_2 = 12 * 3

P_2 = 36

6 0
2 years ago
PLEASE HELP! ! ! urgent!
sertanlavr [38]

Answer:

6(\frac{1}{3} \times\frac{7}{5} )=(6\times\frac{1}{3} )\frac{7}{5}

Answer: B

<u>-------------------------</u>

Hope it helps...

Have a great day!!

8 0
3 years ago
Bella and Heather put some money into their money boxes every week. The amount of money (y), in dollars, in their money boxes af
Hatshy [7]

Answer:

\boxed{ \text{B. 10 weeks, \$310 }}\\

Step-by-step explanation:

We have two conditions:

\begin{array}{lrcll}(1) & y & = & 25x + 60 & \\(2) & y & = & 30x + 10 & \\ & 25x + 60 & = & 30 x + 10 & \text {Set (1) = (2)} \\ & 50 & = & 5x & \text{Subtracted 25x from each side} \\& x & = & 10 &\text{Divided each side by 5} \\\end{array}\\$ $\\\boxed{ \textbf{The number of weeks is }x = 10}\\

   

    Bella: y = 25x + 60 = 25(10) + 60 = 250 + 60 = 310  

Heather: y = 30x + 10  = 30(10) +  10 = 300 + 10  = 310

7 0
3 years ago
Da + ca<br><img src="https://tex.z-dn.net/?f=da%20%2B%20ca" id="TexFormula1" title="da + ca" alt="da + ca" align="absmiddle" cla
sergejj [24]

Answer:

\boxed{a(c + d)}

Step-by-step explanation:

da + ca =  a(c + d)

4 0
2 years ago
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