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max2010maxim [7]

3 years ago

13

The Zurn family ate at a restaurant that was having a 15% discount on that day.Their meal costs $64.75,and they left a 20% tip.W

hat is the total cost of the meal?

1 answer:

My name is Ann [436]3 years ago

4 0

Answer:C

Step-by-step explanation:

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Write an equation in slope intercept form for the line that travels through (1,-2) and (6,8)

MariettaO [177]

Answer:

y=2/1x

Step-by-step explanation:

Subtract (6,8) by (1, -2)

8--2/6-1=10/5

Simply

10/5=2

Plug in

y=2x

3 0

3 years ago

Your bank statement shows that you have a balance of $412.20. All the checks you have written during this statement period are o

mina [271]

Missing check = $412.20 - $331.60 = $80.6

Hope it helps!

3 0

3 years ago

Which of the following equations have a solution of y = -22 ? Select all that apply.

nevsk [136]

Answer:

Where are the equations?

7 0

3 years ago

The product of two numbers is 2400 iftheir LCM is 120 find their LCM.... BY STEPS!!.....

aliina [53]

Answer:

60 and 40 or 120 and 20

Step-by-step explanation:

60 x 2=120

40 x 3=120

60 x 40=2400

120 x 1=120

20 x 6=120

120 x 20=2400

You can try a few others, but no others have an lcm of 120

4 0

4 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

3 years ago

Read 2 more answers