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Greeley [361]
2 years ago
6

Pls help im rlly confused

Mathematics
1 answer:
irina1246 [14]2 years ago
3 0

Answer:

the y intercept is (0,29)

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The measured weights of 1,000 men in a certain village follow a normal distribution with a mean of 150 pounds and a standard dev
Hitman42 [59]
Z = (X-Mean)/SD 
<span>z1 = (165 - 150)/15 = +1 </span>
<span>z2 = (135 - 150)/15 = - 1 </span>
<span>According to the Empirical Rule 68-95-99.7 </span>
<span>Mean +/- 1SD covers 68% of the values </span>
<span>100% - 68% = 32% </span>
<span>The remaining 32% is equally distributed below z = - 1 and z = +1 </span>
<span>32%/2 = 16% 
</span>
<span>Therefore, 
</span>
<span>a) Number of men weighing more than 165 pounds = 16% of 1000 = 160 </span>
<span>b) Number of men weighing less than 135 pounds = 16% of 1000 = 160</span>
3 0
3 years ago
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Write an equation or inequality to represent "five times the difference of a number n and forty two is ten more than twice the p
IRINA_888 [86]

Five times the difference of a number n and forty two is ten more than twice the product of a number x and number y

  • Five times: 5 ×
  • difference of a number n and forty two: (n - 42)
  • is: =
  • twice the product of a number x and a number y: 2(xy)
  • ten more than: + 10

Rewrite the expression into an equation.

<h3>5(n - 42) = 2(xy) + 10</h3>
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3 years ago
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CAN SOMEBODY HELP ME WITH THIS PROBLEM PLZZZ
kvv77 [185]

Answer:

c

Step-by-step explanation:

6 0
4 years ago
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Suppose you were to draw all possible samples of size 36 from a large population with a mean of 650 and a standard deviation of
Lady_Fox [76]

Answer:

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 650 and a standard deviation of 24.

This means that \mu = 650, \sigma = 24.

Sample of 36:

This means that n = 36, s = \frac{24}{\sqrt{36}} = 4

What is the shape of the sampling distribution you would expect to produce?

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

7 0
3 years ago
Write the fraction in its simplest form.<br><br> 6/8
Tcecarenko [31]
It's 3/4 because the only factor you can divide them both with is 2 and 3 and 4 have noi factors to divide by to make it lower.
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