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GarryVolchara [31]
3 years ago
11

HHHHHEEEEEELLLLLPPPPP Parker drove a total distance of 4 and 1 over 2 miles during the months of June and July. If Parker only d

rove 1 over 8 of a mile every day, which expression shows the number of days he went driving? 4 and 1 over 2 ⋅ 1 over 8 4 and 1 over 2 + 1 over 8 4 and 1 over 2 ÷ 1 over 8 4 and 1 over 2 – 1 over 8
Mathematics
2 answers:
goldenfox [79]3 years ago
8 0

Answer:

use cymath for answer

Step-by-step explanation:

it will explain better

levacccp [35]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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Sandra has $20 in a savings account that earns 5% annually. The interest
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20*5%= 20* 0.05=1 , and 1 year= 365 days, so 1 *355=$355 in one year I think, but I’m not sure how to use the formula
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3 years ago
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Points C and D lie on circle O as shown below. If OC = 6x+2 and OD = 10x -16, then find the length of the radius of circle O.
Ket [755]
Radius = OC = OD

Solve for x:

10x -16 = 6x+2

4x = 18

x = 9/2 = 4.5

Sub 'x' back into OC

OC = 6(4.5) + 2 = 29

Radius = 29
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3 years ago
there are n counters in a bag. 4 of the counters are red and the rest are blue. Ross takes a counter from the bag at random and
Ainat [17]

Answer: n = 10.

Step-by-step explanation:

In the bag, we have n counters.

4 of the counters are red.

the rest are blue, then we have:

(n - 4) blue counters.

Now, the probability that Ross takes a blue counter from the bag is equal to the quotient between the number of blue counters (n - 4) and the total number of counters, n

Then the probability is:

p1 = (n - 4)/n

Now he draws another, and it must be blue again, then we can calculate the probability in the same way as above, but he already take a blue counter, so the number of blue counters is (n - 5) and the total number of counters is (n - 1)

The probability of this event is:

p2 = (n - 5)/(n - 1)

The joint probability (the probability that Ross takes two blue counters) is equal to the product of the individual probabilities, and we know that this is equal to 1/3, then we have the equation:

1/3 = ( (n - 4)/n)*((n - 5)/(n - 1))

Now let's solve this for n.

n*(n - 1)/3 = (n - 4)*(n - 5)

(n^2 - n)/3 = n^2 - 4*n - 5*n + 20

n^2 - n = 3*(n^2 - 9*n + 20)

n^2 - n = 3*n^2 - 27*n + 60

0 = (3*n^2 - n^2) - 27*n + n + 60

0 = 2*n^2 - 26*n + 60

The two solutions of this equation can be found with Bhaskara's equation:

n = \frac{-(-26) +- \sqrt{(-26)^2 - 4*2*60} }{2*2} = \frac{26+- 14}{4}

Then the two solutions are:

n = (26 - 14)/4 = 3

This is not an option, because we know for sure that we have 4 red counters, then this option can be discarded.

The other solution is:

n = (26 + 14)/4 = 40/4 = 10

Then we have n = 10, 10 counters in total.

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3 years ago
What does y equal in the equation 4(2y-3)-2y=24?
makvit [3.9K]

Answer:

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Answer:

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