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2 years ago

PLEASE HELP ILL GIVE BRAINLIEST The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?

Mathematics

2 answers:

Lapatulllka [165]2 years ago

8 0

Answer:

(-8,0) (-1,0) (4,0)

Step-by-step explanation:

Just look at where y=0

worty [1.4K]2 years ago

5 0

Answer:

-8, -1 and 4

Step-by-step explanation:

look at where the line meets the x-axis and at what point

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A. dashed line, shade below

Ronch [10]

Answer:

the answer is A

Step-by-step explanation:

3 0

3 years ago

You buy Apple stock for $120 per share over a period of time the stock value increased at a weekly rate of 5% you sell the stock

Rainbow [258]

Answer:

8.31 weeks

Step-by-step explanation:

Given that the cost of one share of Apple stock, C=$120

Rate is the increment of the stock value, R= 5%/week=0.05 / week.

Assuming that after t week, the stock has been sold for $180.

Since the stock value increased at 5% every week, so, the interest is compounded weekly, so

$S=C\left(1+R\right)^t \\\\ \Rightarrow 180 = 120\left(1+0.05\right)^t \\\\ \Rightarrow 180 = 120\left(1.05 )^t \\\\$

$\Rightarrow \frac{180}{120}=1.05^t \\\\\Rightarrow 1.5=1.05^t$

$\Rightarrow \ln(1.5)=t \ln(1.05)$ [taking log both sides]

$\Rightarrow t=\frac {\ln(1.5)}{\ln(1.05)}=8.31$ weeks

Hence, after 8.31 weeks the stock has been sold for $180.

6 0

3 years ago

If the pattern rule is defined by the equation `t = 6n`, where `t` is the term value and `n` is the term number, what is the one

blagie [28]

Answer:

600

Step-by-step explanation:

Given

equation t = 6n

n is term number

we have to find 100th term.

Thus, term number is 100

substituting 100 in place of n in equation t=6n , we can find the value of 100th term

t = 6*100 = 600

Thus, 100th term is 600.

8 0

3 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

4 years ago

Joshua has $24.He used 5/8of his money.How much money did he spend

zhenek [66]

So 5/8 of $24
5/8 * 24
15

Joshua spent $15.

Hope this helps :)

5 0

3 years ago