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777dan777 [17]
3 years ago
7

Final Shot John Diggle needs to give up his trusted Glock for a more non-lethal weapon. Cisco Ramon builds him a stun gun that h

is claims matches the Glock shooting characteristics, including accuracy. Do these data representing "shot groups" give statistically significant evidence of a difference in accuracy between the two type?
Glock (cm): 9.3 16.7 7.1 14 5 6
Stun Gun (cm): 4.9 14.1 7 7.2 5.4 8.6

Write the Hypotheses:
H_0:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
H_a:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
Are the conditions for inference met? (draw a picture of the histograms)


Provide the calculations:
Sample mean diff:_________________________________
Standard err:_____________________________________
T-stat:__________________________________________
P-value:_________________________________________
Write your conclusion:
At the 5% level of significance, we ______________ that the mean difference in ___________ between ____________ and ______________ is _______________. We ________________________ the mean difference in ___________ between ____________ and ______________ is _______________. [P-value = ________ ]
Construct a 90% Confidence interval.

What does the interval mean in the context of the problem

We are 90% confident that the difference in mean _______________
For ________________________ is between ____________ and _______________ ___________________ than __________________.
Was Cisco correct, does John’s Stun Gun perform the same? Explain
Mathematics
1 answer:
lidiya [134]3 years ago
7 0
The h in p will start the p and the glock I believe
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HELP!
givi [52]

Answer:

c?

Step-by-step explanation:

3 0
2 years ago
18 2by5-4 1by10 find the difference
luda_lava [24]

Given:

The expression is:

18\dfrac{2}{5}-4\dfrac{1}{10}

To find:

The difference.

Solution:

We have,

18\dfrac{2}{5}-4\dfrac{1}{10}

It can be rewritten as:

=\dfrac{90+2}{5}-\dfrac{40+1}{10}

=\dfrac{92}{5}-\dfrac{41}{10}

Taking LCM, we get

=\dfrac{184-41}{10}

=\dfrac{143}{10}

=\dfrac{140+3}{10}

=14\dfrac{3}{10}

Therefore, the value of the difference is 14\dfrac{3}{10}.

3 0
3 years ago
Answer for Brainliest<br><br> 1)7/4+5/8=<br> 2)3/2+4/3=<br> 3)2/3+10/7=<br> 4)4-3/17
Sunny_sXe [5.5K]

Answer:

See below.

Step-by-step explanation:

1) 7/4 + 5/8

= 14/8 + 5/8

= 19/8 or 2 3/8

2) 3/2 + 4/3

= 9/6 + 8/6

= 15/6

= 5/2 or 2 1/2

3) 2/3 + 10/7

= 14/21 + 30/21

= 44/21 or 2 2/21

4) 4 - 3/17

= 68/17 - 3/17

= 65/17 or 3 14/17

5 0
2 years ago
Read 2 more answers
How do i solve this -6n-20=2n+4(1-3n)
Leno4ka [110]
Hi Ivan

-6n - 20 = 2n + 4(1 - 3n)
-6n - 20 = 2n + 4 - 12n
Combine like terms
-6n - 20 = 2n - 12n + 4
-6n - 20 = -10n + 4
-6n + 10n = 4 + 20
4n = 24
n = 24/4
n= 6

I hope that's help! If you have any further questions please let me know !
3 0
3 years ago
Find the equation of the midline of the function y = 2 sin(1∕4x) – 3.
Aneli [31]
<h3>Answer:  A) y = -3</h3>

Explanation:

The general sine equation is

y = A*sin(B(x-C)) + D

where the D variable directly determines the midline. In this case, D = -3, so that corresponds to a midline of y = -3

The sine curve oscillates going up and down, passing through this middle horizontal line infinitely many times. See the graph below.

5 0
3 years ago
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