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777dan777 [17]
3 years ago
7

Final Shot John Diggle needs to give up his trusted Glock for a more non-lethal weapon. Cisco Ramon builds him a stun gun that h

is claims matches the Glock shooting characteristics, including accuracy. Do these data representing "shot groups" give statistically significant evidence of a difference in accuracy between the two type?
Glock (cm): 9.3 16.7 7.1 14 5 6
Stun Gun (cm): 4.9 14.1 7 7.2 5.4 8.6

Write the Hypotheses:
H_0:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
H_a:_______________, the mean difference in ___________ between ____________ and ______________ is _______________
Are the conditions for inference met? (draw a picture of the histograms)


Provide the calculations:
Sample mean diff:_________________________________
Standard err:_____________________________________
T-stat:__________________________________________
P-value:_________________________________________
Write your conclusion:
At the 5% level of significance, we ______________ that the mean difference in ___________ between ____________ and ______________ is _______________. We ________________________ the mean difference in ___________ between ____________ and ______________ is _______________. [P-value = ________ ]
Construct a 90% Confidence interval.

What does the interval mean in the context of the problem

We are 90% confident that the difference in mean _______________
For ________________________ is between ____________ and _______________ ___________________ than __________________.
Was Cisco correct, does John’s Stun Gun perform the same? Explain
Mathematics
1 answer:
lidiya [134]3 years ago
7 0
The h in p will start the p and the glock I believe
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Maggie tells you she is deciding between two jobs for which the pay is calculated by the functions A(x) = 5x+20 B(x) = 20x+5 Exp
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B(x) is the better option

Step-by-step explanation:

Let's say that these functions represent the pay f(x) in hours, x. Function B would increase linearly on a greater scale because each X is being multiplied by 20.

You'll notice this trend for larger numbers, such as 10.

A(x) = 5(10) + 20 = 70

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Find the linear approximating polynomial for the following function centered at the given point a.point a. b. Find the quadratic
ZanzabumX [31]

Answer:

(a)L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\(b)Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\(c)L(-0.23\pi)=-0.6626\\Q(-0.23\pi)=-0.6613

Step-by-step explanation:

Given the function:

f(x)=sin x, a=-\frac{\pi}{4}

(a)Linear approximating polynomial

L(x)=f(a)+f'(a)(x-a)\\f(a)=sin(-\frac{\pi}{4})=-\frac{\sqrt{2} }{2}\\f'(x)=cos x, a=-\frac{\pi}{4}\\f'(a)=cos (-\frac{\pi}{4})=\frac{\sqrt{2} }{2} \\Therefore:\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x-(-\frac{\pi}{4}))\\L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})

(b)Quadratic approximating polynomial

Q(x)=L(x)+\frac{1}{2}f''(a)(x-a)^2\\f''(x)=-sin(x), \\f''(a)=-sin(-\frac{\pi}{4})=\frac{\sqrt{2} }{2}\\Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2

(c)When x=-0.23\pi

Using Linear Approximation polynomial

L(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})\\L(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})\\L(-0.23\pi)=-0.6626

Using the Quadratic approximating polynomial

Q(x)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(x+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(x+\frac{\pi}{4})^2\\Q(-0.23\pi)=-\frac{\sqrt{2} }{2}+\frac{\sqrt{2} }{2}(-0.23\pi+\frac{\pi}{4})+\frac{\sqrt{2} }{4}(-0.23\pi+\frac{\pi}{4})^2=-0.6613

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Work out x² -11x+18=0
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Answer: x=2 or x=9

Step-by-step explanation:

Step 1: Factor left side of equation.

(x−2)(x−9)=0

Step 2: Set factors equal to 0.

x−2=0 or x−9=0

x=2 or x=9

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2 years ago
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