8x10 to the fifth power is how many more times as great as 8x10 to the -1 power

<img src="https://tex.z-dn.net/?f=%28m-9%29%28m-3%29" id="TexFormula1" title="(m-9)(m-3)" alt="(m-9)(m-3)" align="absmiddle" cla

Luda [366]

Answer:

m^2-11m+27

Step-by-step explanation:

7 0

3 years ago

write an equation for a circle with a diameter that has endpoints at (-4, -7) and (-2, -5). round to the nearest tenth if necess

andrezito [222]

Answer:

The answer to your question is (x + 3)² + (y + 6)² = 2

Step-by-step explanation:

Endpoints (-4, -7) and (-2, -5)

Process

1.- Find the length of the radius

d = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }$

d = $\sqrt{(-2 + 4)^{2}+ (-5 + 7)^{2} }$

d = $\sqrt{2^{2} + 2^{2} }$

d = $\sqrt{4 + 4}$

d = $\sqrt{8}$

Radius = $\frac{\sqrt{8} }{2}$ = $\sqrt{2}$

2.- Find the center

Xm = $\frac{-4 - 2}{2} = \frac{-6}{2} = -3$

Ym = $\frac{-7 - 5}{2} = \frac{-12}{2} = -6$

Center = (-3, -6)

3.- Write the equation

(x - h)² + (y - k)² = r²

(x + 3)² + (y + 6)² = ( $\sqrt{2}$ )²

(x + 3)² + (y + 6)² = 2

3 0

3 years ago

QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

6 0

3 years ago

10ac-x/11=-3 solve for a

Masja [62]

1) You'll have to get raid of the fraction by multiplying 10ac by 11, x/11 by 11 which the 11's cancels out and -3 multiplied by 11 .
2)Now you have 10ac -x = -33. Add x on both sides of the equal sign you get 10ac = -33 + x
3) Divide both sides by 10c to get "a" by itself, so "a" = -33+x divided by 10c

4 0

3 years ago

Read 2 more answers

Please solve with working thankyou

Lisa [10]

Answer:

m∠y=72°

Step-by-step explanation:

The question is

Find the measure of angle y

step 1

Find the measure of angle x

see the attached figure to better understand the problem

we know that

m∠x=67° -----> by corresponding angles

step 2

Find the measure of angle y

we know that

(m∠x+m∠y)+42°=180° -----> because form a straight line

substitute the measure of angle x

67°+m∠y+42°=180

m∠y+108°=180

m∠y=180°-108°

m∠y=72°

4 0

3 years ago