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zloy xaker [14]
3 years ago
6

How many cups are in a gallon

Mathematics
2 answers:
Digiron [165]3 years ago
6 0
1 cup: 8 oz
1 pint: 2 cups
2 pints: 1 quart
4 quarts: 1 gallon
by looking at this scale you will multiply the needed #s:
2 times 2 = 4    4 times 4 = 16 so there are 16 cups in a gallon 
bija089 [108]3 years ago
3 0
The answer to this question is: 16 us customary cups.
Hope this helps! (:
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AfilCa [17]

Answer:

b = 115.4 feet

Step-by-step explanation:

b^2 = a^2 + c^2 - 2 (a)(b) x cos B

b^2 = 230^2 + 360^2 - 2(230)(360) x cos(38 degrees)

b^2 = 52,900 + 129,600 - 2(230)(360) x cos(38 degrees)

b^2 = 182,500 - 165,600 x cos(38 degrees)

b = \sqrt{(16,900)(cos(38)) }

b = 115.4 feet

i hope this helps!! :)

8 0
2 years ago
Pat has 3 rows of shells. There are 4 shells in esch row. how many shells does pat have?
vazorg [7]

Answer:

The answer is 12

Step-by-step explanation:


3 0
3 years ago
A plastic box has a length 4 cm longer than its width. The area of the rectangular top of the box is 77 square cm. Find the leng
finlep [7]

Answer: the length is 11 cm.

The width is 7 cm.

Step-by-step explanation:

Let L represent the length of the rectangular plastic box.

Let W represent the width of the rectangular plastic box.

The area of the rectangular top of the box is 77 square cm. This means that

LW = 77- - - - - - - ;- - - -1

The plastic box has a length 4 cm longer than its width. This means that

L = W + 4

Substituting L = W + 4 into equation 1, it becomes

(W + 4)W = 77

W² + 4W = 77

W² + 4W - 77 = 0

W² + 11W - 7W - 77 = 0

W(W + 11) - 7(W + 11) = 0

W - 7 = 0 or W + 11 = 0

W = 7 or W = - 11

Since the width cannot be negative, then W = 7cm

L = 77/7 = 11 cm

4 0
3 years ago
Yesterday, Grace drove 2 1/8 miles. she used 1 1/4
prisoha [69]

Answer:

7/8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Chen writes down a two digit number. He finds out that if he swapped the numbers, it would be three more than the 1/3 of the ori
inna [77]

Answer:

Step-by-step explanation:

From the information given,

Let the two digits that Chen writes down to be p and q

where,

q will be in the unit place and p will be in the tens place.

So, the value of the digit = 10p + q

So, if he swapped the number, he will have 10q + p

However,

the new number determined is thrice more than the 1/3 pf the original number.

i.e

the 1/3rd of the original number = \dfrac{1}{3}(10p+q)

=\dfrac{10p+q}{3}

thrice more than that will be = \dfrac{10p+q}{3} + 3

∴

\dfrac{10p+q}{3} + 3 = 10q+p

multiply through by 3, we have :

10p+q + 9 = 30q + 3p

collecting the like terms, we have:

10p - 3p +q -30q +9 = 0

7p - 29q +9 = 0

7p - 29q = -9

Therefore, p,q lie between 0 and 9

Therefore, the possibility of the original number is p = 7 and q = 2

8 0
4 years ago
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