Answer:
1/π
Step-by-step explanation:
r = the side of the square and the radius of the circle
square area = r∧2/π·r∧2
r∧2 should cancel each other in the numerator and denominator.
The result is 1/π
Answer:
Not a function fails the vertical line test
Step-by-step explanation:
This is not a function. The value of x = -1 goes to two different values of y
This would fail the vertical line test
Answer:
Your answer is
b.9
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Step-by-step explanation:
Answer:
The required expression is 
.
The value of the expression when y=20 is 2.
Step-by-step explanation:
Consider the provided phase.
3 less than the quotient of a number y and 4
The quotient of a number y and 4 can be written as: 
Now 3 less than the quotient of a number y and 4 can be written as:
Hence, the required expression is .
Now evaluate when y=20.
Substitute y=20 in above expression.
Hence, the value of the expression when y=20 is 2.
Answer:
Step-by-step explanation:
The center of the circle is the midpoint of the two end points of the diameter.
Formula
Center = (x2 + x1)/2 , (y2 + y1)/2
Givens
x2 = 4
x1 = - 10
y2 = 6
y1 = - 2
Solution
Center = (4 - 10)/2, (6 - 2)/2
Center = -6/2 , 4/2
Center = - 3 , 2
So far what you have is
(x+3)^2 + (y - 2)^2 = r^2
Now you have to find the radius.
You can use either of the endpoints to find the radius.
find the distance from (4,6) to (-3,2)
r^2 = ( (x2 - x1)^2 + (y2 - y1)^2 )
x2 = 4
x1 = -3
y2 = 6
y1 = 2
r^2 = ( (4 - -3)^2 + (6 - 2)^2 )
r^2 = ( (7)^2 + 4^2)
r^2 = ( 49 + 16)
r^2 = 65
Ultimate formula is
(x+3)^2 + (y - 2)^2 = 65
The radius is √65 = 8.06
