Answer:
(B) is the answer according to my calculations
Step-by-step explanation:
The answer is:
1/5, 0.4, 1/2, 0.75
Just turn the fractions into decimal and compare. If it helped you, plz write comments, rank, thanks, and plz give a brainiest answer. :-)
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Answer:
Given: ∆ABC with the altitudes from vertex B and C intersect at point M, so that BM = CM.
To prove:∆ABC is isosceles
Proof:-Let the altitudes from vertex B intersects AB at D and from C intersects AC at E( with reference to the figure)
Consider ΔBMC where BM=MC
Then ∠CBM=∠MCB......(1)(Angles opposite to equal sides of a triangle are equal)
Now Consider ΔDMB and ΔCME
∠D=∠E.......(each 90°)
BM=MC...............(given)
∠CME=∠BMD........(vertically opposite angles)
So by ASA congruency criteria
ΔDMB ≅ ΔCME
∴∠DBM=∠MCE........(2)(corresponding parts of a congruent triangle are equal)
Adding (1) and (2),we get
∠DBM+∠CBM=∠MCB+∠MCE
⇒∠DBC=∠BCE
⇒∠B=∠C⇒AB=AC(sides opposite to equal angles of a triangle are equal)⇒∆ABC is an isosceles triangle .
Well for problems like this you need to look at what is plotted. And you need to look at the y intercept which is the vertical line and the x intercept which is the horizontal line. I think the answer is B because of what is plotted. I am not 100% sure but I think it is. Let me try to look into it more but what is this for? Hw assignment?
<span> the answr is 412 and 319/500</span>