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sesenic [268]
3 years ago
11

What is the result when 3/8x + 2 1/5 - 3 1/2x - 4 1/10

Mathematics
1 answer:
Anna [14]3 years ago
6 0
It equals to 3/5 and in alternative form is 0.6
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Need help ASAP ! Questions are in the pic
Vedmedyk [2.9K]

Answer: b (-2,3)

Step-by-step explanation:

you substitute the x and y values in (-2,-3) for the x and y in the problem.

3 0
3 years ago
A line has a slope of a and has a y-intercept of (0,b). Which equation represents this line?
Papessa [141]

Step-by-step explanation:

General line equation: y = mx + c, where m is the slope of the line and c is the y-intercept.

We have y = ax + b.

=> y - b = ax

=> y - b = a(x - 0).

The answer is option A.

8 0
3 years ago
Read 2 more answers
Janet has $75 to spend at the mall. She has already spent $28. She wants to buy games that cost $15 each, including tax. Enter t
serg [7]

Answer:

3 games

Step-by-step explanation:

The computation of the maximum number of games that he could buy is shown below:

= Amount available - already spent

= $75 - $28

= $47

If each game cost $15

So, the maximum no of games is

= $47 ÷ $15

= 3.133

= 3 games

3 0
3 years ago
y=c1e^x+c2e^−x is a two-parameter family of solutions of the second order differential equation y′′−y=0. Find a solution of the
vagabundo [1.1K]

The general form of a solution of the differential equation is already provided for us:

y(x) = c_1 \textrm{e}^x + c_2\textrm{e}^{-x},

where c_1, c_2 \in \mathbb{R}. We now want to find a solution y such that y(-1)=3 and y'(-1)=-3. Therefore, all we need to do is find the constants c_1 and c_2 that satisfy the initial conditions. For the first condition, we have:y(-1)=3 \iff c_1 \textrm{e}^{-1} + c_2 \textrm{e}^{-(-1)} = 3 \iff c_1\textrm{e}^{-1} + c_2\textrm{e} = 3.

For the second condition, we need to find the derivative y' first. In this case, we have:

y'(x) = \left(c_1\textrm{e}^x + c_2\textrm{e}^{-x}\right)' = c_1\textrm{e}^x - c_2\textrm{e}^{-x}.

Therefore:

y'(-1) = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e}^{-(-1)} = -3 \iff c_1\textrm{e}^{-1} - c_2\textrm{e} = -3.

This means that we must solve the following system of equations:

\begin{cases}c_1\textrm{e}^{-1} + c_2\textrm{e} = 3 \\ c_1\textrm{e}^{-1} - c_2\textrm{e} = -3\end{cases}.

If we add the equations above, we get:

\left(c_1\textrm{e}^{-1} + c_2\textrm{e}\right) + \left(c_1\textrm{e}^{-1} - c_2\textrm{e}  \right) = 3-3 \iff 2c_1\textrm{e}^{-1} = 0 \iff c_1 = 0.

If we now substitute c_1 = 0 into either of the equations in the system, we get:

c_2 \textrm{e} = 3 \iff c_2 = \dfrac{3}{\textrm{e}} = 3\textrm{e}^{-1.}

This means that the solution obeying the initial conditions is:

\boxed{y(x) = 3\textrm{e}^{-1} \times \textrm{e}^{-x} = 3\textrm{e}^{-x-1}}.

Indeed, we can see that:

y(-1) = 3\textrm{e}^{-(-1) -1} = 3\textrm{e}^{1-1} = 3\textrm{e}^0 = 3

y'(x) =-3\textrm{e}^{-x-1} \implies y'(-1) = -3\textrm{e}^{-(-1)-1} = -3\textrm{e}^{1-1} = -3\textrm{e}^0 = -3,

which do correspond to the desired initial conditions.

3 0
3 years ago
Create a sample of 10 numbers that has a mean of 8.6.
GrogVix [38]

Answer:

10 + 8 + 10 + 10 + 10 + 10 + 8 + 8 + 6 + 6

8 0
3 years ago
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