If you have a graphing calculator set it to radian mode and put these in there.
Answer:
a) All of them are out of charge = 9.31x10⁻¹⁰
b) 20% of them are out of charge = 5.529x10⁻⁴
Step-by-step explanation:
This problem can be modeled as a binomial distribution since
There are n repeated trials and all of them are independent of each other.
There are only two possibilities: battery is out of charge and battery is not out of charge.
The probability of success does not change with trial to trial.
Since it is given that it is equally likely for the battery to be out of charge or not out of charge so probability of success is 50% or 0.50
P = 0.50
1 - P = 0.50
a) All of them are out of charge?
Probability = nCx * P^x * (1 - P)^n-x
Probability = ₃₀C₃₀(0.50)³⁰(0.50)⁰
Probability = 9.31x10⁻¹⁰
b) 20% of them are out of charge?
0.20*30 = 6 batteries are out of charge
Probability =₃₀C₆(0.50)²⁴(0.50)⁶
Probability = 5.529x10⁻⁴
Answer:
r(n)=3n-1
Step-by-step explanation:
<h3>
Answer is 1.5 square meters</h3>
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Work Shown:
The portion of the fabric that is laying across the ground is 2 meters. The portion of the fabric from the ground to the highest point (along the fabric's edge) is 1.5 meters, half of that is 0.75 meters and this is the length of the shadow. We can see this by forming a 30-60-90 triangle. The hypotenuse is 1.5 meters, the short leg is 0.75 meters. The short leg is always half of the hypotenuse of any 30-60-90 triangle, and the short leg is opposite the 30 degree angle.
So this shadow has length of 2 meters and 0.75 meters, making its area be 0.75*2 = 1.5 square meters when the sun is directly overhead at 12 noon
Answer:
The answer is y = 8x - 25
