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3 years ago

The graphs below have the same shape. What is the equation of the red graph?

Mathematics

2 answers:

umka2103 [35]3 years ago

5 0

The answer is D
g(x)= -x^2

irina [24]3 years ago

4 0

I’m so sorry i’m just using my common knowledge but i’m sure that it’s D Please lemme know! have a great day

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Compare these two numbers which one has a greater value <br> 8.5 x 10^23 or<br> 9.99 x 10^21

Cloud [144]

8.5 x 10^23 is bigger because the bigger the exponent, the larger the number.

7 0

3 years ago

If the sum of a number and eight is doubled, the result is three less than the number. Find the number.

nydimaria [60]

Answer:

n = -19

Step-by-step explanation:

2(n+8) = n - 3

2n + 16 = n - 3

2n = n - 19

n = - 19

8 0

3 years ago

2. A bank charges a $10 fee to open an account. Which of the following equations best represents the total amount in the account

Marizza181 [45]

Answer:

B. m = d -10

Step-by-step explanation:

6 0

3 years ago

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The standard size of a rectangular placemat is 14 inches by 16 inches. How much fabric is needed to make 6 standard placemats?

lara31 [8.8K]

Answer:

D. 1,344 in^2

Step-by-step explanation:

The area of the standard placemats is 84 in^2. To make 6 we need to multiply that by 6. 84 in^2*6 is 1,344 in^2. Please rate brainliest. It would really help!

8 0

4 years ago

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Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess

Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill$

$\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2$

4 0

3 years ago

Read 2 more answers