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omeli [17]
2 years ago
6

one deterrent to burglary is to leave your front porch light on all the time if your fixture contains the 23 watt compact fluore

scent bulb at 120 volts and your local power utility cell's energy at ten cents per kilowatt-hour how much will it cost to leave the bulb on for the entire month
Physics
1 answer:
sweet [91]2 years ago
6 0

Answer:

Cost = 165.6 cents = $1.656

Explanation:

First, we will calculate the total energy consumed by the bulb in a month:

E=Pt\\

where,

E = Energy Consumed = ?

P = power = 23 W

t = time = (1 month)(30 days/1 month)(24 h/1 day) = 720 h

Therefore,

E = (23\ W)(720\ h)\\E = 16560\ Wh = 16.56\ Kilowatt-hour

Now, the cost will be:

Cost = P(Unit\ Cost)\\Cost = (16.56\ kilowatt-hour)(10\ cents/kilowatt-hour)

<u>Cost = 165.6 cents = $1.656</u>

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The position-time equation for a cheetah chasing an antelope is:
pochemuha

Answer:

x = 1.6 + 1.7 t^2      omitting signs

a) at t = 0     x = 1.6 m

b) V = d x / d t = 3.4 t

at t = 0     V = 0

c) A = d^2 x / d t^2 = 3.4     (at t = 0  A = 3.4 m/s^2)

d)  x = 1.6 + 1.7 * (4.4)^2 = 34.5    (position at 4.4 sec = 34.5 m)

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2 years ago
A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km. 1. If you and your spacesuit
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1. 0.16 N

The weight of a man on the surface of asteroid is equal to the gravitational force exerted on the man:

F=G\frac{Mm}{r^2}

where

G is the gravitational constant

M=8.7\cdot 10^{13}kg is the mass of the asteroid

m = 100 kg is the mass of the man

r = 2.0 km = 2000 m is the distance of the man from the centre of the asteroid

Substituting, we find

F=(6.67\cdot 10^{-11}m^3 kg^{-1} s^{-2})\frac{(8.7\cdot 10^{13} kg)(110 kg)}{(2000 m)^2}=0.16 N

2. 1.7 m/s

In order to stay in orbit just above the surface of the asteroid (so, at a distance r=2000 m from its centre), the gravitational force must be equal to the centripetal force

m\frac{v^2}{r}=G\frac{Mm}{r^2}

where v is the minimum speed required to stay in orbit.

Re-arranging the equation and solving for v, we find:

v=\sqrt{\frac{GM}{r}}=\sqrt{\frac{(6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2})(8.7\cdot 10^{13} kg)}{2000 m}}=1.7 m/s

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3 years ago
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The frequency of the oscillation in hertz is calculated to be 0.00031 Hz.

The frequency of a wave is defined as the number of cycles completed per second while the period refers to the time taken to complete a cycle. The frequency is the inverse of period.

So;

Period(T) = 54 minutes or 3240 seconds

Frequency (f) = T-1 = 1/T = 1/3240 seconds = 0.00031 Hz

Learn more: brainly.com/question/14588679

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Explanation:

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