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MAVERICK [17]
3 years ago
11

HOW DO YOU SOLVE THIS QUICKLY. GIVING32 POINTS. CONVERT THIS INTO TAN(68) WITH STEPS.

Mathematics
2 answers:
exis [7]3 years ago
6 0

https://www.mathcelebrity.com/anglebasic.php?entry=68&coff=&pl=tan

go to the link

fomenos3 years ago
4 0

Answer:

  • See below

Step-by-step explanation:

<u>Use identities:</u>

  • sin 2x = 2sinxcosx
  • cos 2x = cos²x - sin²x

<u>Simplify the given:</u>

  • sin 2x / (1 - cos 2x) =
  • 2sin x cos x / (sin² x + cos² x - cos² x + sin² x) =
  • 2sin x cos x / 2sin² x =
  • cos x / sin x =
  • cot x = tan (90° - x) (in the quadrant I)

<u>Apply to the given:</u>

  • sin (44°) / (1 - cos (44°)) =
  • tan (90° - 44°/2) =
  • tan (90° - 22°) =
  • tan  (68°)

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Could someone give me an answer and explain how you got it ?
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A (9, 3)

Step-by-step explanation:

First the point is rotated 90° counterclockwise about the origin.  To do that transformation: (x, y) → (-y, x).

So S(-3, -5) becomes S'(5, -3).

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3 0
3 years ago
I need help with this ASAP plzzzzz
miss Akunina [59]

Answer:

23. \frac{4\sqrt{3} }{3}

24. \frac{7\sqrt{3}}{3}

25. 6\sqrt{3}

26. \frac{10\sqrt{3} }{3}

27.  14

28. 4\sqrt{3}

Step-by-step explanation:

To solve these i used SOHCAHTOA

sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}

23.

Find the missing side using Tangent

tan(30)=\frac{x}{4}

4*tan(30)=x

\frac{4\sqrt{3} }{3}

24.

Find the missing side using Tangent

tan(30)=\frac{x}{7}

7*tan(30)=x

\frac{7\sqrt{3}}{3}

25.

Find the missing side using Tangent

tan(30)=\frac{x}{18}

18*tan(30)=x

6\sqrt{3}

26.

Find the missing side using Tangent

tan(30)=\frac{x}{10}

10*tan(30)=x

\frac{10\sqrt{3} }{3}

27.

Find the missing side using Tangent

tan(30)=\frac{x}{14\sqrt{3} }

(14\sqrt{3}) *tan(30)=x

14

28.

Find the missing side using Tangent

tan(30)=\frac{x}{12}

12*tan(30)=x

4\sqrt{3}

5 0
3 years ago
Write the inequality and SOLVE<br> 4 times a number increaded by 14 is at most 30
serg [7]
The answer would be 4 x 4 = 16+14= 30
3 0
3 years ago
8 times of the eight term of an arithmetic progression is equal to 12 times of the twelfth term. find its first term if the comm
denpristay [2]

Answer:

38

Step-by-step explanation:

We can express the 8th term as x and the 12th term as y.

This would mean that 8x=12y

Because the common difference between terms is -2 and term 8 and term 12 are 4 terms apart, this means that the 12th term is 8 less than the 8th term, so x-8=y

Now we can use this to substitute y with x in the first equation. This would give us:

8x=12(x-8)

Which we can expand and solve:

8x=12x-96

-4x=-96

Therefore x=24

This means the 8th term is 24 and the 12th term is 16 (24-8).

To test if this is correct we can do:

8x24=12x16

Which indeed are equal, both sides multiply to 192.

Now that we have our 8th term, we can find the 1st term, which is 7 terms away, therefore we just add 14 to the 8th term 24. (7x2=14)

24+14=38.

The first term is 38.

Hope this helped!

3 0
3 years ago
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