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Artyom0805 [142]
3 years ago
10

I hat is the slope 6/-10 and 3/-13

Mathematics
1 answer:
tatiyna3 years ago
6 0

Answer:

1

Step-by-step explanation:

Assuming your mean we have the points

(6, -10) and ( 3, -13)

We can use the slope formula

m = (y2-y1)/(x2-x1)

m = ( -13 - -10)/( 3 - 6)

    = (-13+10)/( 3-6)

   = -3 / -3

    = 1

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3 years ago
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3 years ago
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just olya [345]
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
                                         0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
                                         t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
                                           = [- 12 ± √(144-64d) ] / (-32)
                                           = [- 12 ± √16(9-4d)] / (-32)
                                           = [- 12 ± 4√(9-4d)] / (-32)
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The answer to your question is t = 3/8 ±√(9-4d) / 8
5 0
4 years ago
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