Answer: its either A or C, but im p sure its C
Answer:
Step-by-step explanation:
Triangle 1,
Sum of the squares of the shorter lengths = 13² + 17²
= 169 + 289
= 458
Square of the longest length = 19² = 361
Since, sum of longest side is less than sum of squares of the smaller sides,
13²+ 17² > 19²
Therefore, it's acute triangle.
Triangle 2,
Sum of squares of the shorter lengths = 10² + 24²
= 576
Square of the largest length = 26² = 576
Since, sum of squares of the shorter lengths = square of the largest length
Therefore, it's a right triangle.
X 1 2 3 4
p(x) 0.40 0.20 0.15 ?
If the items are only 4. The total of the probability must be 1 or 100%
1 - 0.40 - 0.20 - 0.15 = 0.25
The probability of 4 is 0.25.
The data 5, 3, 6, 8, 7, 8, 3, 11, 10, 3, 2 would have a mean of
KengaRu [80]
Answer:
The mean of a set of number is the sum divided by the number of terms.
The data 5, 3, 6, 8, 7, 8, 3, 11, 10, 3, 2 would have a mean of <u><em>6</em></u>
<u><em></em></u>
I hope this helps you!!!!
Answer:
FV(p)= PV*(1 + g)^t
Step-by-step explanation:
Giving the following information:
Number of insects (PV)= 1,500
Increase rate= 3 weekly
<u>First, we need to calculate the daily growth rate:</u>
Daily rate (g)= [3^(1/7)] - 1
Daily rate (g)= 0.16993
<u>Now, by using the following formula, we can determine the population p in any given day t:</u>
FV(p)= PV*(1 + g)^t
<u>For, example after 7 days:</u>
FV(p)= 1,500*(1.16993^7)
FV(p)= 4,500
<u>For example, after 10 days:</u>
FV(p)= 1,500*(1.16993^10)
FV(p)= 7,206
