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madreJ [45]
3 years ago
6

I need help with this question please

Mathematics
1 answer:
padilas [110]3 years ago
3 0

Answer:

Value of a is 26 and vaule of b is 12

Step-by-step explanation: May i get brainlesist

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Answer:

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Factorise mx+cx+my+cy<br> With steps!!!<br> x=algebra x
avanturin [10]

Step-by-step explanation:

Hey there!

While factorising you remember to make it take common in most of the expression.

Here;

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= x(m+c) + y(m+c)

Now, "(m+c)" common again.

= (m+c) (x+y)

Therefore the factorized form of the expression in (m+c)(x+y).

<u>Hope it helps</u><u>.</u><u>.</u><u>.</u>

6 0
3 years ago
Read 2 more answers
Particle 1 of charge q1 �� ��5.00q and particle 2 of charge q2 �� ��2.00q are fixed to an x axis. (a) as a multiple of distance
Naya [18.7K]

<span>Assuming that the particle is the 3rd particle, we know that it’s location must be beyond q2; it cannot be between q1 and q2 since both fields point the similar way in the between region (due to attraction). Choosing an arbitrary value of 1 for L, we get </span>

<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>

Rearranging to calculate for d:

<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
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<span>
We pick the value that is > q2 hence,</span>

d = 2.72075922005613*L

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3 0
3 years ago
What is 3.81704*10^5?
myrzilka [38]

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1 year ago
Please help with my Sequences Hw<br><br> I will give brainliest
lions [1.4K]
Geometric with a common ratio of 4/3

9*4/3 = 12
12*4/3= 16
16 *4/3 =21 1/3
8 0
3 years ago
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