Question

Determine the brake horsepower required by a pump for a discharge of 0.2 m3/s and a total dynamic head of 20m, with an efficiency of 80%.

Answer 1

Answer:

The BHP would be "65.659 HP".

Explanation:

The given values are:

Discharge,

Q = 0.2 m³/s

Dynamic head,

H = 20 m

Efficiency,

% = 80%

Now,

The Power will be:

⇒ $P=\delta QH$

On substituting the values, we get

⇒     $=1000\times 9.81\times 0.2\times 20$

⇒     $=39240 \ W$

The brake horse power will be:

⇒ $BHP=\frac{100 Q H}{3960n}$

On putting values, we get

⇒           $=\frac{100\times 0.2\times 20}{3960\times 0.80}$

⇒           $=65.659 \ HP$