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3 years ago

Help me with this hw please

Mathematics

1 answer:

zvonat [6]3 years ago

3 0

Answer:

12 = 3 + p

Step-by-step explanation:

She has a total of 12 pencils

3 of them are red

The rest are "p"

p + 3 must equal 12 because she has a total of 12 pencils consisting of 3 red and "p" as the rest

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A 68-year old retiree has a pension savings of $43,000, a 401k of $75,000, and an IRA account of $62,000. Before 2008, he had 2%

Natalija [7]

Answer:

The answer is the IRA

Step-by-step explanation:

If he takes out 2% from each account, the highest penalty will be for the IRA account which is, 6% of 62,000 is $3,720. He will also take 2% of that 62,000 which will be $1,240. The total will be $4,960.

For the 401k account the withdrawal is $1,500 and the penalty is $3,000. That is $460 less than the IRA account.

I hope this answer helps.

6 0

2 years ago

Read 2 more answers

Plz help me with this

shtirl [24]

2x-7y=18 _(1)
-2x+4y=5

11y=23 , Y=23/11 sub in 1

2x-7×23/11=18

2x = 18×11 + 7×23

x = ( 198 + 161 )/2 = 359/2

5 0

4 years ago

If f(x)=| x-2 |, then find f(-3)

GenaCL600 [577]

The value of f(-3) is 5.

In order to find this answer, we are going to input -3 in for x (this is what the notation f(-3) means).

f(x)=| x-2 |

f(-3)=| -3 -2 |

f(-3)=| -5 |

Now we have to take the absolute value.

f(-3) = 5

3 0

3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ <em>(Approximated)</em>

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ <em>(Approximated)</em>

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

3 years ago

Raju finished his work in 5/6 hour.Vrinda finished her work in 3/4 hour .who worked longer ? By what fraction was it longer

Nataly [62]

Answer:

Raju worked longer by 0.08 hours.

3 0

3 years ago