Answer:
Option A.
Step-by-step explanation:
The given question is incomplete. Here is the complete question.
P(n) models the price (in dollars) of a pack of n bulbs at a certain store.
When does the price of a pack increase faster ?
n 4 10 12
P(n) 12 25 28
When does the price of a pack increase faster ?
A. Between 4 and 10 bulbs
B. Between 10 and 12 bulbs
C. The price increases at the same rat over both the intervals.
To solve this question we will find the rate of increase in the prices per pack in the given intervals.
From n = 4 to n = 10
Rate of increase in price = 
= 
= 2.166 ≈ $2.17 per pack
From n = 10 to n = 12
Rate of increase in price = 
= 
= $1.5 per pack
Therefore, price per pack increases faster between n = 4 and n = 10 as compared to n = 10 to n = 12.
Option A is the answer.
If you observe that 
, you can rewrite the expression as
Now, if you use the exponent rule 
, you may rewrite the expression again:
Answer:
Li Jing's formula i.e. 
is right.
Step-by-step explanation:
Considering the sequence
A geometric sequence has a constant ratio r and is defined by
So, the sequence is geometric.
as
so
Therefore, Li Jing's formula i.e. is right.
Similarities:
Have a consistent change for every interval can be represented as functions of a variable points lie on a line.
Differences: linear equations represent all solutions to all x values, whereas arithmetic sequences pick integer spacing
9514 1404 393
Answer:
$2400
Step-by-step explanation:
The question is asking the amount invested in fund B. We can let 'b' represent that amount. Then the amount invested in fund A is (6000-b). The total profit from the investments is ...
0.02(6000 -b) +0.07(b) = 0.04(6000)
120 +0.05b = 240 . . . . . simplify
0.05b = 120 . . . . . . . . . subtract 120
b = 2400 . . . . . . . . . . .divide by 0.05
Alonzo invested $2400 in fund B.
