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nlexa [21]
3 years ago
12

Use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

Mathematics
1 answer:
Elis [28]3 years ago
8 0
<span>5x= 6x^2 -3
</span><span>6x^2 -5x -3
a = 6
b = -5
c = -3

x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- </span><span>sq root (25 -(4*6*-3)] / 12
</span><span>x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- </span><span>9.84886] / 12
x1 = </span><span><span><span>1.237405 </span> </span> </span>  <span>
x2 = </span><span><span><span>-0.404072 </span> </span> </span>



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Interpret f(2) = 5120.
Olin [163]

Answer:

2560

Step-by-step explanation:

5120 divided by 2

f=2560

5 0
3 years ago
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3 0
2 years ago
What digit makes each number divisible by nine?<br><br> _7,302
Alborosie

Answer:

Not completely sure but hopefully these will help.

Step-by-step explanation:

I'm kind of confused what you're asking for. If you could clarify that would be great. If you're trying to make it divisible by 9, you can either do 3, 6 or 9. If you want the first two digits: 2,5,8. Please clarify so I can help

8 0
4 years ago
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! I NEED TO FINISH THESE QUESTIONS BEFORE MIDNIGHT TONIGHT.
hoa [83]

Answer:

The answer to your question is AC = 9.9

Step-by-step explanation:

To solve this problem use trigonometric functions. The trigonometric function that relates the hypotenuse and the adjacent side is cosine.

             cos α = \frac{adjacent side}{hypotenuse}

Solve for hypotenuse

              hypotenuse = \frac{adjacent side}{cos\alpha }

Substitution

             hypotenuse = \frac{9}{cos 24}

Simplification and result

             hypotenuse = 9.85

6 0
3 years ago
Y=1/3x+4 going through the point (9,-2)
Art [367]
Substitute x=9 and y=-2 into equation,
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Because LHS doesn’t = with RHS, the point (9,-2) doesn’t satisfy with the equation

Therefore the point doesn’t go through y=1/3x +4.
5 0
3 years ago
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