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nlexa [21]
3 years ago
12

Use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

Mathematics
1 answer:
Elis [28]3 years ago
8 0
<span>5x= 6x^2 -3
</span><span>6x^2 -5x -3
a = 6
b = -5
c = -3

x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- </span><span>sq root (25 -(4*6*-3)] / 12
</span><span>x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- </span><span>9.84886] / 12
x1 = </span><span><span><span>1.237405 </span> </span> </span>  <span>
x2 = </span><span><span><span>-0.404072 </span> </span> </span>



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