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nlexa [21]
3 years ago
12

Use the quadratic formula to solve 5x=6x^2-3, what are the values of x?

Mathematics
1 answer:
Elis [28]3 years ago
8 0
<span>5x= 6x^2 -3
</span><span>6x^2 -5x -3
a = 6
b = -5
c = -3

x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- </span><span>sq root (25 -(4*6*-3)] / 12
</span><span>x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- </span><span>9.84886] / 12
x1 = </span><span><span><span>1.237405 </span> </span> </span>  <span>
x2 = </span><span><span><span>-0.404072 </span> </span> </span>



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Step-by-step explanation:

To form a linear equation from two points lie on the line which the equation represented it

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∵  Points (-2 , -4) and (-3 , -3) lie on the line

∴ x_{1} = -2 and x_{2} = -3

∴ y_{1} = -4 and y_{2} = -3

- Substitute these values in the formula of the slope

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∴ m = -1

∵ The form of the equation is y = m x + b

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∴ y = (-1) x + b

∴ y = -x + b

To find b substitute x and y in the equation by the coordinates of

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∴ -3 = -(-3) + b

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Learn more:

You can learn more about linear equation in brainly.com/question/4326955

#LearnwithBrainly

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