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liberstina [14]
3 years ago
12

when a ball is dropped onto a flat floor , it bounces to 65% of the height from which it was dropped. if the ball is dropped fro

m 80 cm, find the height of the fifth bounce.
Mathematics
1 answer:
34kurt3 years ago
8 0
The height of the fifth bounce
80x65%x65%x65%x65%x65%
=9.282325 cm
You might be interested in
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sveta [45]

Answer:

18/14=64+7%×r try it out

8 0
2 years ago
The perimeter of an inceles triangle is 21 meters. The length of one
sdas [7]

Answer:

The sides are 6, 6 and 9

Step-by-step explanation:

Isosoles triangles have two sides the same length, s

Here the third side is 3 meters longer (s + 3)

therefor the perimeter is

s + s + (s + 3) = 21

Combine like terms

3s + 3 = 21

Subtract 3 from both sides

3s = 18

Divide both sides by 3

s = 6

s + 3 = 9

The sides are 6, 6 and 9

6 0
2 years ago
Help me please :(( it would mean a lot
krok68 [10]
Q: -10, 3
R: -4, 3
S: -4, 2
T: -10, 2
3 0
3 years ago
Write the equation of the line that passes through the given points.<br> (0,4) and (5,10)
Lunna [17]

Answer: y = 6/5x + 4

Step-by-step explanation: The equation is in form y = mx + b, where m is the slope and b is the y-intercept. You already have the y-intercept, which is 4. To find the slope, use rise over run. y2 - y1 / x2 - x1 = 10-4/5-0 = 6/5.

5 0
3 years ago
. The manager of a local small bank wants to estimate the average daily balance of all the checking accounts. Assume a random sa
MaRussiya [10]

Answer:

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

Step-by-step explanation:

Consider the provided information.

A random sample of 21 checking accounts at the bank are chosen,

That means n=21

df = n-1

df = 21-1=20

We need to  Construct and interpret a 95% confidence interval.

Determine t critical value for 95% confidence interval.

0.95=1-α

α=0.05

The sample size is small and it is a two tailed test.

From the t value table confidence interval is 2.086

An average daily balance is $303 and a standard deviation of $63.

CI=\bar x\pm t_c \times \frac{s}{\sqrt{n}}

Substitute the respective values.

CI=303\pm 2.086 \times \frac{63}{\sqrt{21}}

CI=303\pm 28.68

CI=274.32\ or\ 331.68

A 95% confidence interval estimate of the population mean (average) daily balance of all the checking accounts is $274.32 to $331.68

3 0
3 years ago
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