If x=1
1/3x = 1/3
3x = 3
If x=2
1/3x=2/3
3x=6
If x=3
1/3x=1
3x=9
If x=4
1/3x=1 1/3
3x+12
Answer:
a) The mass is released at t = 0 when h is minimum. Half a cycle later h reaches its maximum and another half a cycle it reaches its minimum again. Hence over one cycle, h varies with t as follows:
b) According to the graph obtained in part a), h(t) could be modeled by a cosine function shifted (translated) vertically up and horizontally to the right. Hence
Step-by-step explanation:
So the first one is -0.5 and second is -0.5 the third one is -0.5 and the fourth is -0.25 so I would say that is D
Answer:
a. x > 0.2
Step-by-step explanation:
In either order, subtract the left-side constant and divide by the x-coefficient.
3x +2.4 > 3
3x > 0.6 . . . . . . subtract 2.4
x > 0.2 . . . . . . . divide by 3
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or
x + 0.8 > 1 . . . . divide by 3
x > 0.2 . . . . . . . subtract 0.8
It would cost $132. 7+7+15+15X3=132