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icang [17]
4 years ago
9

How do you add 4 digit numbers

Mathematics
1 answer:
ValentinkaMS [17]4 years ago
5 0
The way you add 4 digit numbers is by taking each place value and adding them each together. One's get added with ones, tens get added with tens and so on. For example, to add 1864+7528, you would first start off with adding 4 and 8 which gives you 12. The 2 will go under the equation and the 1 will travel to the tens place. Next, 2+6 which is 8 and then add the 1 from 12 which gives you 9. Then, 8+5 which is 13. Again, the 3 will go under the equation and the 1 will travel to the thousands place. Finally, 7+1 which is 8 and then add the 1 from 13 which gives you 9. The sum should be 9392.
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Please help.. I’m stuck on this question
s2008m [1.1K]

Answer: The answer is 1

Step-by-step explanation: The distance between -7 and -3 is 4 then half the distance in between -7 and -3 is going to be -5 because we just clarified that the distance between -7 and -3 is 4 so we did 4/2 and got 2 so we can figure out whats the distance between each point. Now that we figured that out we can determine what value the blue dot is if the value between each point is 2 then we can make out what the rest of the points on the line. If we from -3 to the blue point that would be 1.

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Nathan had an infection, and his doctor wanted him to take penicillin. Because Nathan’s father and paternal grandfather were all
asambeis [7]

The answer is 0.2450

To calculate this, a multiplication rule is used. The multiplication rule calculates the probability that both of two events will occur. In this method, the probabilities of each event are multiplied.

In this situation, we have two events occurring simultaneously:

1. Nathan is not allergic to penicillin. The probability that Nathan is not allergic to penicillin is:

1 - the probability of having the allergy.

If the probability of having the allergy is 75% = 0.75, then the probability that Nathan is not allergic to penicillin is:

1 - 0.75 = 0.25

2. The probability that the test is accurate: 98% = 0.98

By using the multiplication rule:

0.25 × 0.98 = 0.245

Therefore, the probability after the test that Nathan is not allergic to the drug is 0.245 = 24.5%.

4 0
3 years ago
Read 2 more answers
Assume that when adults with smartphones are randomly​ selected, 58​% use them in meetings or classes. If 10 adult smartphone us
Tasya [4]

Answer:

79.85% probability that at least 5 of them use their smartphones in meetings or classes.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they use their smartphone during meetings or classes, or they do not. The probability of an adult using their smartphone in these situations are independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Assume that when adults with smartphones are randomly​ selected, 58​% use them in meetings or classes.

This means that p = 0.58

10 adults selected.

This means that n = 10

Find the probability that at least 5 of them use their smartphones in meetings or classes.

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{10,5}.(0.58)^{5}.(0.42)^{5} = 0.2162

P(X = 6) = C_{10,6}.(0.58)^{6}.(0.42)^{4} = 0.2488

P(X = 7) = C_{10,7}.(0.58)^{7}.(0.42)^{3} = 0.1963

P(X = 8) = C_{10,8}.(0.58)^{8}.(0.42)^{2} = 0.1017

P(X = 9) = C_{10,9}.(0.58)^{9}.(0.42)^{1} = 0.0312

P(X = 10) = C_{10,10}.(0.58)^{10}.(0.42)^{0} = 0.0043

P(X \geq 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.2162 + 0.2488 + 0.1963 + 0.1017 + 0.0312 + 0.0043 = 0.7985

79.85% probability that at least 5 of them use their smartphones in meetings or classes.

3 0
4 years ago
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