We set up an equation for this. P = 2L + 2W.24 = 2(3W-8) + 2W
24 = 6W + 2W -16
32 = 8W
W = 4.
L = 3W-8
L = 3 (4) -8
L = 12-8
L = 4
-3
step by step
add 2 to -11 and divide-9 by 3
Answer:
71300
Step-by-step explanation:
3a+b+c
The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.
So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:
16a+8b-6c - 2*(5a+3b-4c) =
16a+8b-6c -10a-6b+8c =
6a+2b+2c
half of that is
(6a+2b+2c)/2 = 3a+b+c
<h3>
Answer: </h3><h3>Fred has <u>20 students</u> and Lee has <u>22 students</u></h3>
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Work Shown:
L = number of students in Lee's class
F = number of students in Fred's class
Lee has 1.1 times as many students compared to Fred
This means we have this equation
L = 1.1F
Whatever the value of F is, we multiply that by 1.1 to get the value of L
The two amounts L and F add to 42 total students
L+F = 42
1.1F + F = 42 .... replace L with 1.1F
2.1F = 42
F = 42/(2.1)
F = 20 .... Fred has 20 students
L = 1.1*F
L = 1.1*20
L = 22 .... Lee has 22 students
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Check:
L+F = 22+20 = 42
this confirms the answer