She was at 40 feet below, she swam up getting so she was then at 40-10 = 30 feet below sea level.
She the swan 4 feet down so she ended up at 30 + 4 = 34 feet below sea level.
The answer is 34 feet below sea level (-34)
Answer:
A: C=45h+30
B: C=$322.50
Step-by-step explanation:
A: We'll start with the equation for the total charge. Juan is saying he will pay a one time fee of $30, meaning there is 30 dollars added to what ever the hourly wage is. This can be represented by the +30. Now if "h" represents the variable for which the hourly wage will be calculated, and he pays $45 dollars per hour this will be represented as 45h. <em>As an example if I pay you 2 dollars per hour using the same variable "h", this would be represented as 2h. So if you worked for two hours you would get 4 dollars, this is proven by the fact the 2(2) (remeber im replacing the "h" with the hours you worked) obviously 2 times 2 is 4 proving my point. </em>This information will give you the equation you see above.
B: Onto solving for how much Juan will pay. Now you say youre supposed to have 9 answer but this can't be true. All you need to do is plug the hours given into "h" and solve the equation. It should look something like:
<u>C=45h+30</u>
<u>C=45(6.5)+30</u>
Im using a decimal because it should be clear 1/2=0.5
<u>C= 292.5+30</u>
45x6.5 always go with PEMDAS, we are multiplying first. Then add 292.5 plus 30
This results in the answer of:
<u>C=$322.50</u>
Answer:
i think it is 43
Step-by-step explanation:
Answer:
He needs to sell 100 souvenirs
Step-by-step explanation:
We want to know the number of souveniers John has to sell
Let the number of souveniers he sold at the game be s
At a rate of $0.25 per souvenier, the amount earned on souveniers for s souveniers will be:
![0.25 \times s =0.25s](https://tex.z-dn.net/?f=0.25%20%5Ctimes%20s%20%3D0.25s)
Now, if we added this to the amount he earns per game, we will have the total $35 earned for working at one game.
Thus, mathematically:
![0.25s + 10 = 35 \\ 0.25s = 35 - 10 \\ 0.25s = 25 \\ s = \frac{25}{0.25} \\ s = 100](https://tex.z-dn.net/?f=0.25s%20%2B%2010%20%3D%2035%20%5C%5C%200.25s%20%3D%2035%20-%2010%20%5C%5C%200.25s%20%3D%2025%20%5C%5C%20s%20%3D%20%20%5Cfrac%7B25%7D%7B0.25%7D%20%20%5C%5C%20s%20%3D%20100)
So.. hmm notice the picture here
we know the length is 59 more than twice the width,
twice the width, 2 * w, or 2w
59 more than that
2w + 59
we also know that, whatever that is, the diagonal of it is,
2 more inches than that, or
(2w + 59) + 2
now.. use the pythagorean theorem
![\bf c^2=a^2+b^2\implies \qquad \begin{cases} a=2w+59\\ b=w\\ c=(2w+59)+2\to 2w+61 \end{cases} \\\\\\ (2w+61)^2=(2w+59)^2+(w)^2 \\ \qquad\qquad \uparrow\qquad \qquad\qquad \qquad \uparrow \\ \textit{expand using binomial theorem, or FOIL}](https://tex.z-dn.net/?f=%5Cbf%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Aa%3D2w%2B59%5C%5C%0Ab%3Dw%5C%5C%0Ac%3D%282w%2B59%29%2B2%5Cto%202w%2B61%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0A%282w%2B61%29%5E2%3D%282w%2B59%29%5E2%2B%28w%29%5E2%0A%5C%5C%20%20%5Cqquad%5Cqquad%20%5Cuparrow%5Cqquad%20%5Cqquad%5Cqquad%20%5Cqquad%20%5Cuparrow%20%20%5C%5C%0A%5Ctextit%7Bexpand%20using%20binomial%20theorem%2C%20or%20FOIL%7D)
you'd end up with a quadratic, after simplifying, solve for "w"