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Scilla [17]
3 years ago
13

Simplify -1 – 8i —3— 51

Mathematics
1 answer:
ad-work [718]3 years ago
7 0

Answer: 1=8i

Step-by-step explanation:

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Marco need to buy some dog food at the nearest store six bags of dog food cost $25.50 how much would Marcos bag of five bags of
julsineya [31]

Answer:

Five bags of dog food costs $21.25.

Step-by-step explanation:

We can solve using proportions.

\frac{6 \: bags}{25.50 \: dollars}  =  \frac{5 \: bags}{x}   \\  \\  \frac{127.5}{6}  =  \frac{6x}{6}  \\  \\ 21.25 = x \\ 21.25 \: dollars = x

5 0
3 years ago
25 to 75 in ratio lowest term
ANTONII [103]
25 to 75 in lowest terms:

25:75 = 1:3
8 0
3 years ago
Substitution again help please
Vesnalui [34]

Answer:

Step-by-step explanation:

1) 4x -3

x = -7 ;

4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31

x = 14 ;

4x - 3 = 4*14 - 3 = 56 - 3 = 53

x = 0

4x - 3 = 0 - 3 = -3

2) 6 -3x

x = -7 ;

6 - 3x = 6 - 3*(-7) = 6 + 21 = 27

x = 14

6 - 3x = 6 - 3*14 = 6 - 42 = -36

x = 0

6 - 3x = 6 - 0 = 6

3) \dfrac{3x - 21}{7}\\\\x = -7\\\\\\\dfrac{3*(-7)-21}{7}=\dfrac{-21-21}{7}=\dfrac{-42}{7}=-6\\\\\\x = 14\\\\\dfrac{3*14-21}{7}=\dfrac{42-21}{7}=\dfrac{21}{7}=3\\\\\\x=0\\\\\dfrac{0-21}{7}=\dfrac{-21}{7}=-3\\\\

4)

\dfrac{3x}{7}-21\\\\\\x = -7\\\\\dfrac{3*(-7)}{7}-21=-3-21=-24\\\\\\x =14\\\\\dfrac{3*14}{7}-21=3*2-21=6-21=-15\\\\\\x=0\\\\\dfrac{0}{7}-21=-21

8 0
2 years ago
I am Pat, Good Legs Lance, and Colorado Bronze are horses in a horse race. Their probabilities of winning the race are as follow
Veseljchak [2.6K]

Answer: Colorado Bronze , I am pat wins, good legs lance wins

6 0
3 years ago
Which are the solutions of x2 = –11x + 4? StartFraction negative 11 minus StartRoot 137 EndRoot Over 2 EndFraction comma StartFr
Marysya12 [62]

Answer:

x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}

Step-by-step explanation:

Given the following quadratic equation:

x^2 = -11x + 4

The steps to solve it are:

1. Move the terms to one side of the equation:

x^2+11x- 4=0

2. Apply the Quadratic formula x=\frac{-b\±\sqrt{b^2-4ac} }{2a}.

In this case we can identify that:

a=1\\b=11\\c=-4

Then, substituting these values into the Quadratic formula we get the following solutions:

x=\frac{-11\±\sqrt{11^2-4(1)(-4)} }{2(1)}

x_1=-\frac{11}{2}-\frac{\sqrt{137} }{2}\\\\x_2=-\frac{11}{2}+\frac{\sqrt{137} }{2}

3 0
3 years ago
Read 2 more answers
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