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Pani-rosa [81]
2 years ago
12

Find the value of x for the right triangle. trigonometric ​

Mathematics
1 answer:
damaskus [11]2 years ago
8 0

Here's the solution,

The given triangle is a right angled triangle,

So, by Using Trigonometry :

=》

\sin(30)  =  \dfrac{x}{13}

=》

\dfrac{1}{2}  =  \dfrac{x}{13}

=》

x =  \dfrac{13}{2}

=》

x = 6.5

hence, value of x = 6.5 units

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Answer:

20 x 20 feet

Step-by-step explanation:

First I just drew out two squares, one was the first un-cut square and the second is the cut one. Since we know that the area of the smaller square is 144, and Area is just side^2 , we know that all the sides of the smaller square are 12. Now, all we have to do is add 8 to 12 to get the original lawn. The original lawn was a 20 x 20 ft lawn.

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2 years ago
D = 8a The variable a represents the number of attendees, and the variable d represents the cost in dollars. At most how many at
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Answer: At most 9  attendees can be there.

Step-by-step explanation:

Given equation:<em> d = 8a</em> , where <em>a</em> represents the number of attendees, and the variable <em>d </em>represents the cost in dollars.

To find : the number of attendees, if Will budgets a total of $72 for his graduation picnic.

72=8a

⇒ 9 = a  [divide both sides by 8]

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Read 2 more answers
A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength
irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

<u><em>Let </em></u>\bar X<u><em> = sample mean comprehensive strength</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean comprehensive strength = 5500 psi

            \sigma = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P(\bar X > 4985 psi)

    P(\bar X > 4985 psi) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{4985-5500}{\frac{100}{\sqrt{9} } } ) = P(Z > -15.45) = P(Z < 15.45)

                                                                  = <u>0.99999</u>

<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>

4 0
3 years ago
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